Question

下面的方法总是在目录中搜索名为＆＃34; level.dat＆＃34;的特定文件。返回null：

-snip-
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\DIM1\##MCEDIT.TEMP##
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\DIM1\##MCEDIT.TEMP2##
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\DIM1\playerdata
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\icon.png
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\level.dat
We found a match: C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\level.dat
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\level.dat_old
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\mcedit_waypoints.dat
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\playerdata
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\playerdata\4e879a3b-c247-4d9a-8ec8-577172a00356.dat
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\region
C:\Users\mrjvs\AppData\Roaming\the stanley parable\temp\stanleyparablemoesh\The stanley parable for moesh\region\r.-1.-1.mca
-snip-

使用以下方法调用该方法：

{{1}}

wftemp是目录的路径。

通过放置几个println，我发现它确实找到了该文件。但是没有正确回归。印刷品代码：

{{1}}

这是控制台返回的打印行：

{{1}}

我已经尝试了超过1.5小时。我不知道了。

Answer 1

private static File traverse(File dir, String name) {
    if (dir.isDirectory()) {
        String[] children = dir.list();
        for (int i = 0; children != null && i < children.length; i++) {
            File tmp = traverse(new File(dir, children[i]),name.trim());
            if( tmp != null ) {
              return tmp;
            }
        }
    }
    if (dir.isFile()) {
        if (dir.getName().trim().equalsIgnoreCase(name.trim())) {
            return dir;
        }
    }
    return null;
}

如果有多个匹配，则仅返回第一个匹配。再见。

Answer 2

实际上，这并不奇怪，你正试图做一些递归的事情。但是从未使用过对traverse的递归调用。现在它只有在您想要查找的路径上调用它时才会起作用。尝试添加对traverse调用的返回，如下所示：

for (int i = 0; children != null && i < children.length; i++) {
    File result = traverse(new File(dir, children[i]),name.trim());
    if(result != null) {
       return result;
    }
}

目录搜索方法始终返回null

2 个答案: