在推动symfony 1.2中,htmlentities无法正常工作

时间:2016-07-20 13:44:22

标签: php oracle symfony-1.2

问题

  • 用双引号替换单引号

    echo $ movement_data

输出字符串:

    '200407', '200396', '200397', '200398', '200399', '200400', '200401', '200402', '200403', '200404'

推动代码:

         $c->add(VmemberDetailsPeer::PERSON_ID,array(htmlentities($movement_data, ENT_QUOTES)),Criteria::IN);
         echo $c->toString();
         $person = VmemberDetailsPeer::doSelect($c);

推进查询

 Criteria: SQL (may not be complete): SELECT FROM vmember_details WHERE vmember_details.PERSON_ID IN (:p1) Params: vmember_details.PERSON_ID => ''200407', '200396', '200397', '200398', '200399', '200400', '200401', '200402', '200403', '200404''

输出:

   array(0) { }

我需要什么

  • 我需要在where子句中传递相同的逗号分隔字符串。

  • 如果我直接在数组中推送moving_data comm seperated string($ movement_data)

  • 它输出特殊字符,如'\ 2222 \',依此类推......我在where子句中有htmlspecial字符。

不要使用Htmlentities Result推进查询

         SELECT FROM vmember_details 
   WHERE vmember_details.PERSON_ID IN (:p1) 

   Params: vmember_details.PERSON_ID => '\'200407\', \'200396\', \'200397\', \'200398\', \'200399\', \'200400\', \'200401\', \'200402\', \'200403\', \'200404\''

解决方案我尝试使用make make make string to array:

 $x=explode(",",$movement_data);

输出:

      Array
     (
      [0] => '200407'
      [1] => '200396'
      [2] => '200397'
      [3] => '200398'

     )


       $c->add(VmemberDetailsPeer::PERSON_ID,$x,Criteria::IN);
         echo $c->toString();
         $person = VmemberDetailsPeer::doSelect($c);

推进查询输出:

      SELECT FROM vmember_details WHERE vmember_details.PERSON_ID IN (:p1,:p2,:p3,:p4,:p5,:p6,:p7,:p8,:p9,:p10) Params: vmember_details.PERSON_ID => '\'200407\'', vmember_details.PERSON_ID => ' \'200396\'', vmember_details.PERSON_ID => ' \'200397\'', vmember_details.PERSON_ID => ' \'200398\'', vmember_details.PERSON_ID => ' \'200399\'', vmember_details.PERSON_ID => ' \'200400\'', vmember_details.PERSON_ID => ' \'200401\'', vmember_details.PERSON_ID => ' \'200402\'', vmember_details.PERSON_ID => ' \'200403\'', vmember_details.PERSON_ID => ' \'200404\''
  • 我需要传递相同的字符串where子句。

1 个答案:

答案 0 :(得分:1)

您从字符串中提取数据,输出是该数组

$x=explode(",",$movement_data);

Array
(
    [0] => '200407'
    [1] => '200396'
    [2] => '200397'
    [3] => '200398'
)

然后将该数组传递给创建和SQL语句的函数。

好的,现在请看下面的代码示例

$a1 = array(1,2,3);
$a2 = array('1','2','3');
$a3 = array("'1'","'2'","'3'");

print_r($a1);
print_r($a2);
print_r($a3);


Array
(
    [0] => 1
    [1] => 2
    [2] => 3
)
Array
(
    [0] => 1
    [1] => 2
    [2] => 3
)
Array
(
    [0] => '1'
    [1] => '2'
    [2] => '3'
)

第一个数组$ a1包含整数,第二个数组包含带数字的字符串,第三个数组包含数字用单引号包装的字符串

这正是你的问题!

您必须从数字中删除单引号,因为驱动程序会专门处理它们(替换为' by \'),这是您观察到的:

SELECT FROM vmember_details 
WHERE vmember_details.PERSON_ID IN (:p1) 

Params: vmember_details.PERSON_ID => '\'200407\', \'200396\', \'200397\', \'200398\', \'200399\', \'200400\', \'200401\', \'200402\', \'200403\', \'200404\''

事实上,那里发生了一些不同的事情。您传递了一个包含单引号的字符串。驱动程序检查字符串,遇到单引号并用斜杠单引号替换它们。