我想在Ubuntu 10.04上捕获Python 2.6.5中dpkg --list | grep linux-image
的输出。
from subprocess import Popen
from subprocess import PIPE
p1 = Popen(["dpkg", "--list"], stdout=PIPE)
p2 = Popen(["grep", "linux-image"], stdin=p1.stdout, stdout=PIPE)
stdout = p2.communicate()[0]
标准输出的内容是:
>>> print stdout rc linux-image-2. 2.6.31-14.48 Linux kernel image for version 2.6.31 on x86 ii linux-image-2. 2.6.32-22.36 Linux kernel image for version 2.6.32 on x86 ii linux-image-2. 2.6.32-23.37 Linux kernel image for version 2.6.32 on x86 ii linux-image-2. 2.6.32-24.43 Linux kernel image for version 2.6.32 on x86 ii linux-image-2. 2.6.32-25.44 Linux kernel image for version 2.6.32 on x86 ii linux-image-ge 2.6.32.25.27 Generic Linux kernel image
但是,这与在shell中运行dpkg --list | grep linux-image
不同:
cschol@blabla:~$ dpkg --list | grep linux-image rc linux-image-2.6.31-14-generic 2.6.31-14.48 Linux kernel image for version 2.6.31 on x86 ii linux-image-2.6.32-22-generic 2.6.32-22.36 Linux kernel image for version 2.6.32 on x86 ii linux-image-2.6.32-23-generic 2.6.32-23.37 Linux kernel image for version 2.6.32 on x86 ii linux-image-2.6.32-24-generic 2.6.32-24.43 Linux kernel image for version 2.6.32 on x86 ii linux-image-2.6.32-25-generic 2.6.32-25.44 Linux kernel image for version 2.6.32 on x86 ii linux-image-generic 2.6.32.25.27 Generic Linux kernel image
查看第一行,可以看到Python中的输出被截断:
rc linux-image-2. 2.6.31-14.48
而不是
rc linux-image-2.6.31-14-generic 2.6.31-14.48
为什么会这样做?有没有办法在Python中获得完全相同的输出?
答案 0 :(得分:4)
import subprocess
p1 = subprocess.Popen(["dpkg", "--list"], stdout=subprocess.PIPE, env={'LANG':'C'})
p2 = subprocess.Popen(["grep", "linux-image"], stdin=p1.stdout, stdout=subprocess.PIPE)
out,err=p2.communicate()
print(out)
dpkg
命令的输出取决于LANG环境变量的值。
在LANG=C
中设置subprocess.Popen
会使dpkg
的输出更像您从终端看到的内容。
答案 1 :(得分:4)
无需使用grep!
import subprocess
p1 = subprocess.Popen(["dpkg", "--list"], stdout=subprocess.PIPE, env={'LANG':'C'})
out,err=p1.communicate()
for o in out.split("\n"):
if "linux-image" in o:
print o