Question

下面的

是xml文件

<priority-claims>
          <priority-claim sequence="1" kind="national">
            <document-id document-id-type="maindoc">
             <doc-number>FD0297663</doc-number>
             <date>20070403</date>
            </document-id>
          </priority-claim>
          <priority-claim sequence="2" kind="national">
            <document-id document-id-type="maindoc">
              <doc-number>FD0745459P</doc-number>
              <date>20060424</date>
            </document-id>
            </priority-claim>
</priority-claims>

我的预期条件：

1.如何获得所有节点值（即FD0297663, 20070403 and FD0745459P,20060424）

2.its可以是单个（即Priority -claim标签）或多于一个级别

我的现有代码仅获得第一级值

String priorityNumber = xPath.compile("//priority-claim//doc-number").evaluate(xmlDocument);
 String priorityDate = xPath.compile("//priority-claim//date").evaluate(xmlDocument);

Answer 1

以下是一个工作示例：

更新了xpath表达式（例如/priority-claims/priority-claim/document-id/doc-number/text()）

使用NodeList

NodeList priorityNumbers = (NodeList) xPath.compile("/priority-claims/priority-claim/document-id/doc-number/text()").evaluate(xmlDocument, XPathConstants.NODESET);
NodeList priorityDates = (NodeList) xPath.compile("/priority-claims/priority-claim/document-id/date/text()").evaluate(xmlDocument,XPathConstants.NODESET);

for(int i=0; i<priorityNumbers.getLength();i++){
    System.out.println(priorityNumbers.item(i).getNodeValue());
}

for(int i=0; i<priorityDates.getLength();i++){
    System.out.println(priorityDates.item(i).getNodeValue());
}

以下是与具有可运行版本的要点的链接：https://gist.github.com/rparree/1c7eb8e9ca928b98418fdb167a2096a3

获取多个节点值的xpath - 使用java的xml解析器

1 个答案: