Question

我正在获得如下的网络服务响应：

 (
    {
    ChatDetailsID = 1;
    ChatID = 4;
    ChatLine = hI;
    Timestamp = "15-Jul-16 04:30";
    UserID = 2;
},
    {
    ChatDetailsID = 2;
    ChatID = 4;
    ChatLine = "hI!";
    Timestamp = "15-Jul-16 04:30";
    UserID = 6;
},
    {
    ChatDetailsID = 9;
    ChatID = 4;
    ChatLine = "sample string 3";
    Timestamp = "18-Jul-16 05:57";
    UserID = 2;
},
    {
    ChatDetailsID = 10;
    ChatID = 4;
    ChatLine = "sample string 4";
    Timestamp = "18-Jul-16 06:03";
    UserID = 2;
},
    {
    ChatDetailsID = 15;
    ChatID = 4;
    ChatLine = Dsjfrejfijrihfuirhgvurhuifhueirghiurhgvuirhiuvhriuhfiuerhihfrfreg;
    Timestamp = "19-Jul-16 01:11";
    UserID = 2;
}
)

我希望在表视图中显示此数据，但是时间戳作为表视图部分标题和数据，根据时间戳记在下面。

我正在尝试使用一个键和多个对象准备字典，如下所示：

NSMutableDictionary *temDic = [[NSMutableDictionary alloc] init];

for (int j = 0; j<[arrmDate count]; j++)
{
    for (int i =0; i< [arrmMsg count]; i++)
    {
        ChatContainer *object1 = [arrmMsg objectAtIndex:i];

         NSString * strobjdate = object1.strDate;
         NSString * strdate = [arrmDate objectAtIndex:j];

        if ([strdate isEqualToString:strobjdate])
        {
            [temDic setValue:object1.strChatLine forKey:strdate];
        }
    }
}

在上面的代码中，arrmDate是包含不同日期的日期数组，arrmMsg包含容器类的输出，其中我存储了我在Web服务响应中获得的所有值。

但我只得到该特定日期的最后一个值如下：

{
"15-Jul-16" = "hI!";
"18-Jul-16" = "sample string 4";
"19-Jul-16" = Dsjfrejfijrihfuirhgvurhuifhueirghiurhgvuirhiuvhriuhfiuerhihfrfreg;
}

我想要如下：

{
"15-Jul-16" = "hI","hI!";
"18-Jul-16" = "sample string 3","sample string 4";
"19-Jul-16" = Dsjfrejfijrihfuirhgvurhuifhueirghiurhgvuirhiuvhriuhfiuerhihfrfreg;
}

请让我知道我做错了什么。或建议任何其他解决方案。谢谢。

Answer 1

在Dictionary中，只能为特定键存储一个值。 TimeStamp 15-Jul-16 04:30发生两次，因此这个timeStamp（用作键）的第二次值被新值替换。

Answer 2

正如您所看到的，您的第一个字典有let point: CGPoint = CGPoint(x:10,y:10) let dict:NSMutableDictionary = ["point":NSValue(CGPoint: point)] let getVal:CGPoint = (dict["point"] as? NSValue)!.CGPointValue() print(getVal)作为时间戳，第二个字典也有"15-Jul-16 04:30"作为时间戳。

因此，第一次编译器遇到"15-Jul-16 04:30"语句时，它存储了[temDic setValue:object1.strChatLine forKey:strdate]，因为您的词典中没有包含"hI"的键

现在，第二次遇到"15-Jul-16 04:30"语句时，已经有一个[temDic setValue:object1.strChatLine forKey:strdate]的密钥，所以它只是用"15-Jul-16 04:30"替换了该密钥

现在，如果您只是将日期部分存储在"hI!"数组中，它显然无法区分第3和第4个字典，因为arrmdave是{{1}所以它继续替换相同的密钥。

如果要根据时间戳对词典进行排序，那么首先在striate数组中，将timeStamps与日期保持一致，然后使用数组来保存已排序的词典。

"18-Jul-16"

请确保您的arrmdave保留整个日期字符串，例如NSMutableDictionary *temDic; NSMutableArray *sortedList = [[NSMutableArray alloc]init]; for (int j = 0; j<[arrmDate count]; j++) { temDic = [[NSMutableDictionary alloc] init]; NSString *strdate = [arrmDate objectAtIndex:j]; for (int i =0; i< [arrmMsg count]; i++) { ChatContainer *object1 = [arrmMsg objectAtIndex:i]; NSString *strobjdate = object1.strDate; if ([strdate isEqualToString:strobjdate]) { [temDic setValue:object1.strChatLine forKey:strdate]; [sortedList addObject: temDic]; break; } } }而不是arrmDate。

Answer 3

首先，我很抱歉推迟了答案。昨天晚上8点30分，当我发布回答时是 - Stack Overflow目前处于离线状态 进行维护。这就是原因只是我昨天无法发布答案。

Bhagyashree mahajan谢谢你。我试着让解决方案持续了4个小时。最后我根据你的输出得到了。我创建了你的阵列字典。我的回答让你满意。

#import "ViewController.h"

@interface ViewController ()
{
  NSMutableDictionary *dict1,*dict2,*dict3,*dict4,*dict5,*dictResult;
  NSMutableArray *arrJsonResponse,*arrTimeStamp,*arrChatLine;
  NSMutableArray *arrAppendObject,*arrAppendKey;
  NSString *strAppendValue;
}

@end

@implementation ViewController

- (void)viewDidLoad
{
  [super viewDidLoad];
  // Do any additional setup after loading the view, typically from a nib.

  dict1 = [[NSMutableDictionary alloc]initWithObjectsAndKeys:@"1",@"ChatDetailsID",@"4",@"ChatID",@"hi",@"ChatLine",@"15-Jul-16 04:30",@"Timestamp",@"2",@"UserID", nil];
  dict2 = [[NSMutableDictionary alloc]initWithObjectsAndKeys:@"2",@"ChatDetailsID",@"4",@"ChatID",@"hi",@"ChatLine",@"15-Jul-16 04:30",@"Timestamp",@"6",@"UserID", nil];
  dict3 = [[NSMutableDictionary alloc]initWithObjectsAndKeys:@"9",@"ChatDetailsID",@"4",@"ChatID",@"sample string 3",@"ChatLine",@"18-Jul-16 05:57",@"Timestamp",@"2",@"UserID", nil];
  dict4 = [[NSMutableDictionary alloc]initWithObjectsAndKeys:@"10",@"ChatDetailsID",@"4",@"ChatID",@"sample string 4",@"ChatLine",@"18-Jul-16 06:03",@"Timestamp",@"2",@"UserID", nil];
  dict5 = [[NSMutableDictionary alloc]initWithObjectsAndKeys:@"15",@"ChatDetailsID",@"4",@"ChatID",@"Dsjfrejfijrihfuirhgvurhuifhueirghiurhgvuirhiuvhriuhfiuerhihfrfreg",@"ChatLine",@"19-Jul-16 01:11",@"Timestamp",@"2",@"UserID", nil];
  arrJsonResponse = [[NSMutableArray alloc]initWithObjects:dict1,dict2,dict3,dict4,dict5,nil];


  arrTimeStamp = [[NSMutableArray alloc]init];
  arrChatLine = [[NSMutableArray alloc]init];
  arrAppendObject = [[NSMutableArray alloc]init];
  arrAppendKey = [[NSMutableArray alloc]init];
  dictResult = [[NSMutableDictionary alloc]init];


   for(int i=0;i<arrJsonResponse.count;i++)
   {
      NSString *strTimeStamp = [NSString stringWithFormat:@"%@",[[arrJsonResponse objectAtIndex:i] objectForKey:@"Timestamp"]];
      NSString *strChatLine = [NSString stringWithFormat:@"%@",[[arrJsonResponse objectAtIndex:i] objectForKey:@"ChatLine"]];
      NSRange range = [strTimeStamp rangeOfString:@" "];
      strTimeStamp = [[strTimeStamp substringToIndex:NSMaxRange(range)] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
      NSLog(@"The date is - %@",strTimeStamp);
      [arrTimeStamp addObject:strTimeStamp];
      [arrChatLine addObject:strChatLine];
    }

   for(int j=0;j<arrTimeStamp.count;j++)
   {
      NSString *strDate = [arrTimeStamp objectAtIndex:j];
      NSString *strChatLine = [arrChatLine objectAtIndex:j];
      int index = (int)[arrTimeStamp indexOfObject:strDate];
      if(j != index)
      {
          [arrAppendKey removeLastObject];
          [arrAppendObject removeLastObject];
          strAppendValue = [NSString stringWithFormat:@"%@ %@",[arrChatLine objectAtIndex:index],[arrChatLine objectAtIndex:j]];
          [arrAppendObject addObject:strAppendValue];
          [arrAppendKey addObject:strDate];
       }
       else
       {
          [arrAppendObject addObject:strChatLine];
          [arrAppendKey addObject:strDate];
       }
    }
    NSLog(@"The objects are - %@",arrAppendObject);
    NSLog(@"The keys are - %@",arrAppendKey);

   for (int k=0;k<arrAppendKey.count;k++)
   {
      NSString *strArrKey = [NSString stringWithFormat:@"%@",[arrAppendKey objectAtIndex:k]];
      NSString *strArrObject = [NSString stringWithFormat:@"%@",[arrAppendObject objectAtIndex:k]];
      [dictResult setObject:strArrObject forKey:strArrKey];
   }
   NSLog(@"The printed dictionary results are - %@",dictResult);
}

印刷结果

 The objects are -
 (
  "hi hi",
   "sample string 3 sample string 4",
   Dsjfrejfijrihfuirhgvurhuifhueirghiurhgvuirhiuvhriuhfiuerhihfrfreg
 )
 The keys are - 
 (
  "15-Jul-16",
  "18-Jul-16",
  "19-Jul-16"
 )

The printed dictionary results are - 
{
  "15-Jul-16" = "hi hi";
  "18-Jul-16" = "sample string 3 sample string 4";
  "19-Jul-16" = Dsjfrejfijrihfuirhgvurhuifhueirghiurhgvuirhiuvhriuhfiuerhihfrfreg;
}

以上代码完美无缺。

iOS：UITableview，相应地插入部分和数据

3 个答案: