从多列文件中提取行

Question

我有以下格式的数据集：

Identified_____ID#2357_____ReadSequence:1238  
Unknown_____0_____ReadSequence:0979  
Unknown_____0_____ReadSequence:5476  
Identified_____ID#567899_____ReadSequence:4376  

使用awk命令，如何提取ReadSequences但仅提取已识别的行（基于第一列条目）？

Answer 1

$ awk -F"_____" '$1=="Identified" {print $3}' test.in 
ReadSequence:1238
ReadSequence:4376

如果您只想要ReadSequence ID，gsub是您的朋友：

$ awk -F"_____" '$1=="Identified" {gsub(/^.*:/,"",$3); print $3}' test.in 
1238
4376 

Answer 2

awk -F'_____' '/^Identified/ {print $NF}' file
ReadSequence:1238
ReadSequence:4376

OR

awk '/^Identified/ {split($0,a,"_____");print a[3]}' info
ReadSequence:1238
ReadSequence:4376

如果您只想读取ReadSequence的值，那么

awk -F'_____' '/^Identified/ {split($NF,a,":"); print a[2]}' file
1238
4376

Answer 3

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