Question

我有这段代码：

public class Connexion extends Activity {

    EditText etResponse;
    TextView tvIsConnected;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_connect);

        // get reference to the views
        etResponse = (EditText) findViewById(R.id.etResponse);
        tvIsConnected = (TextView) findViewById(R.id.tvIsConnected);

        // check if you are connected or not
        if(isConnected()){
            tvIsConnected.setBackgroundColor(0xFF00CC00);
            tvIsConnected.setText("You are conncted");
        }
        else{
            tvIsConnected.setText("You are NOT conncted");
        }

        // call AsynTask to perform network operation on separate thread
        new HttpAsyncTask().execute("https://10.0.2.2:29422/service/MBBS/TWVpblRlc3RJRGRlc2dlcmFldHMxNTA3MjAxNjE0MTgyMTMyMC41MzQzMjk2NDM0ODM2NDY2/customer");
    }

    public static String GET(String url){
        InputStream inputStream = null;
        String result = "";
        try {
            HttpClient httpclient = new DefaultHttpClient();

            // make GET request to the given URL
            HttpResponse httpResponse = httpclient.execute(new HttpGet(url));

            // receive response as inputStream
            inputStream = httpResponse.getEntity().getContent();

            // convert inputstream to string
            if(inputStream != null)
                result = convertInputStreamToString(inputStream);
            else
                result = "Did not work!";

        } catch (Exception e) {
            Log.d("InputStream", e.getLocalizedMessage());
        }

        return result;
    }

    private static String convertInputStreamToString(InputStream inputStream) throws IOException {
        BufferedReader bufferedReader = new BufferedReader( new InputStreamReader(inputStream));
        String line = "";
        String result = "";
        while((line = bufferedReader.readLine()) != null)
            result += line;

        inputStream.close();
        return result;
    }

    public boolean isConnected(){
        ConnectivityManager connMgr = (ConnectivityManager) getSystemService(Activity.CONNECTIVITY_SERVICE);
        NetworkInfo networkInfo = connMgr.getActiveNetworkInfo();
        if (networkInfo != null && networkInfo.isConnected())
            return true;
        else
            return false;
    }
    private class HttpAsyncTask extends AsyncTask<String, Void, String> {
        @Override
        protected String doInBackground(String... urls) {
            return GET(urls[0]);
        }
        // onPostExecute displays the results of the AsyncTask.
        @Override
        protected void onPostExecute(String result) {
            Toast.makeText(getBaseContext(), "Received!", Toast.LENGTH_LONG).show();
            etResponse.setText(result);
        }
    }
}

我试图通过模拟器对这个问题进行鉴定：＆＃34; https://10.0.2.2:29422/service/MBBS/TWVpblRlc3RJRGRlc2dlcmFldHMxNTA3MjAxNjE0MTgyMTMyMC41MzQzMjk2NDM0ODM2NDY2/customer＆＃34;

我无法通过笔记本电脑访问相同的内容：＆＃34; https://localhost:29422/service/MBBS/TWVpblRlc3RJRGRlc2dlcmFldHMxNTA3MjAxNjE0MTgyMTMyMC41MzQzMjk2NDM0ODM2NDY2/customer＆＃34;这项工作

任何想法？

Answer 1

由于我的声望不是+50，我写在这里。

仿真器与服务器运行时在同一台PC上工作，因此可以访问localhost 如果要访问移动设备中Localhost上运行的服务器，则必须：

- ＆GT;如果您的设备和系统位于同一LAN上，则可以使用系统的IP地址

如果您不知道系统的IP地址，请使用：

ipconfig        //Windows
ifconfig        //Linux

OR

- ＆GT;为运行服务器的系统分配静态IP

HttpAsyncTask无法访问localhost

1 个答案: