Question

我试图按月每个日期获取所有数据。

我有这张桌子。我在sqlfiddle创建它时遇到问题。

CREATE TABLE Outlet
(
    IdOutlet [int] NOT NULL,
    OutletCode [varchar](100) NOT NULL,
    Description [varchar](225) NULL
);

出口记录

1 | K-AEON   | Desc1
2 | K-LFTEJM | Desc2

和这张表

CREATE TABLE [dbo].[SalesOrderHeader]
(
    [TransactionNo] [varchar](32) NOT NULL,
    [DocumentNo] [varchar](32) NOT NULL,
    [TransDate] [datetime] NOT NULL,
    [ETADate] [datetime] NOT NULL,
    [ExternalDocument] [varchar](32) NOT NULL,
    [Reference] [varchar](64) NOT NULL,
    [RefTransNo] [varchar](32) NOT NULL,
    [Category] [varchar](32) NOT NULL,
    [CustomerCode] [varchar](16) NOT NULL,
    [Remark] [varchar](64) NOT NULL,
    [Remark2] [varchar](64) NOT NULL,
    [TermOfPayment] [datetime] NOT NULL,
    [Currency] [varchar](16) NOT NULL,
    [Rate] [decimal](38, 20) NOT NULL,
    [UseVAT] [int] NOT NULL,
    [SubTotal] [decimal](38, 20) NOT NULL,
    [DiscPercent] [decimal](38, 20) NOT NULL,
    [DiscAmount] [decimal](38, 20) NOT NULL,
    [GrandTotal] [decimal](38, 20) NOT NULL,
    [TotalReceivable] [decimal](38, 20) NOT NULL,
    [FromCustomerCode] [varchar](32) NOT NULL,
    [PostingStatus] [int] NULL,
    [PostingBy] [varchar](16) NULL,
    [PostingDate] [datetime] NULL,
    [CreatedDate] [datetime] NOT NULL,
    [CreatedBy] [varchar](16) NOT NULL,
    [ModifiedDate] [datetime] NOT NULL,
    [ModifiedBy] [varchar](16) NOT NULL,
    [CustomerReceivable] [varchar](16) NULL,
    [LocationCode] [varchar](16) NOT NULL,
    [VatPercent] [float] NOT NULL,
    [VatAmount] [float] NULL,
    [FinalReleasedDate_Outlet] [datetime] NULL,
    [CancelStatus] [int] NULL,
    [CancelReason] [varchar](100) NULL,
    [CancelledBy] [varchar](50) NULL,

    CONSTRAINT [PK__SalesOrd__554342D81FCDBCEB] 
    PRIMARY KEY CLUSTERED ([TransactionNo] ASC)
          WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, 
                IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON,
                ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]

如你所见，我有两张桌子。现在我有了这个查询来获取我的所有数据。

select 
    CustomerCode, CONVERT(date, transdate) tanggal,
    SUM(totalreceivable) total 
from 
    SalesOrderHeader 
where 
    TransDate between '$start_date' and '$end_date'
group by 
    CONVERT(date, transdate), CustomerCode

以下是一个示例结果

K-AEON      2016-07-18  2841600.00000000000000000000
K-LFTEJM    2016-07-17  4862190.00000000000000000000

但我想要这个结果

            |1 | 2 | 3 |  4-16  |      17      |   18      | 19-29 |30|
   K-AEON   |..|   |   | ...... |    2841600   |           | ..... |..|
  K-LFTEJM  |..|   |   |        |              |  4862190  |       |..|

我怎样才能实现这一目标？我可以使用什么方法？

我想把它放在sqlfiddle上，但我得到了这个结果Create script error

抱歉我的英语。

Answer 1

考虑您的示例结果，

    DECLARE @T AS TABLE (NAME VARCHAR(50), TransDate DATETIME, TotalReceivable DECIMAL(38, 20))

    INSERT INTO @T VALUES ('K-AEON', '2016-07-18', 2841600.00000000000000000000)
    INSERT INTO @T VALUES ('K-LFTEJM', '2016-07-17' ,4862190.00000000000000000000)

    SELECT * FROM (SELECT day(Transdate) DayOfTrans,*FROM @T) T
    PIVOT(Max(TotalReceivable) FOR DayOfTrans 
     IN ([1], [2], [3], [17], [18], [19], [20])) FinalRes

所需的输出是，

Name        TransDate               1       2       3       17      18      19      20
--------    ----------------------- ------- ------- ------- ------- ------- ------- ------- 
K-LFTEJM    2016-07-17 00:00:00.000 NULL    NULL    NULL  4862190.00000000000000000000 NULL  NULL  NULL
K-AEON      2016-07-18 00:00:00.000 NULL    NULL    NULL  NULL  2841600.00000000000000000000 NULL  NULL

Answer 2

对于选定的日期;

CREATE TABLE #Test (OutletCode VARCHAR(50), Date_ DATETIME, TotalAmount DECIMAL(38, 20))

DECLARE @SelectedDate DATETIME = '2016.07.01'
DECLARE @CountOfDay INT = 1
DECLARE @DayCountForSelectedMonth INT = DATEDIFF(day, @SelectedDate, dateadd(month, 1, @SelectedDate))
DECLARE @Days NVARCHAR(MAX)
DECLARE @Query NVARCHAR(MAX)

INSERT INTO #Test VALUES ('K-AEON', '2016-07-18', 2841600.00000000000000000000)
INSERT INTO #Test VALUES ('K-LFTEJM', '2016-07-17' ,4862190.00000000000000000000)


;WITH CountOfDayTable(CountOfDay)
AS
(
    SELECT @CountOfDay
    UNION ALL
    SELECT CountOfDay + 1
    FROM CountOfDayTable
    WHERE CountOfDay < @DayCountForSelectedMonth
)

SELECT 
     @Days = COALESCE(@Days + ', ','') + '[' + CAST(CountOfDay AS NVARCHAR(4)) + ']'
FROM CountOfDayTable C
-- SELECT @Days -- [1], [2], [3], [4], [5], [6], [7], [8], [9], [10], [11], [12], [13], [14], [15], [16], [17], [18], [19], [20], [21], [22], [23], [24], [25], [26], [27], [28], [29], [30], [31]

SET @Query = 

    'SELECT * FROM (SELECT day(Date_) DayOfTrans, * FROM #Test) T
    PIVOT(Max(TotalAmount) FOR DayOfTrans IN  -- OR MIN
            (' +
                    @Days
               +    
            ')
        ) FinalRes';

-- SELECT @Query
EXEC sp_executesql @Query

显示每个日期，即使它没有价值

2 个答案: