Question

我在根据爆炸获取数据时遇到了一些问题。

示例，如果我有一个$cuisines_category的数组：

string(26) "Breakfast/Cake - Accept voucher/New Restaurant""

从该数组中有2个内容数据，Breakfast/Cake为$cuisines_name_all，Accept voucher/New_Restaurant为$facility_name_all。

到目前为止，我可以返回爆炸数据，以下代码：

$split=array_map('trim', explode("-",$cuisines_category));
$cuisines_name_all = (isset($split[0]) === TRUE ? $split[0] : 0);
$facility_name_all = (isset($split[1]) === TRUE ? $split[1] : 0);

$cuisines_name = explode("/", $cuisines_name_all);
$facility_name = explode("/", $facility_name_all);

我的问题是，如果数组$cuisines_category只为$facility_name_all作为此数组的内容怎么样：

string(30) "Online payment available/Deals"

所以我用这段代码更改了我的爆炸代码：

$split=array_map('trim', explode("-",$cuisines_category));
$cuisines_name_all = (isset($split[0]) === TRUE ? $split[0] : 0);
if(isset($split[1])){
    $facility_name_all = $split[1];
}else{
    $facility_name_all = $split[0];
}

$cuisines_name = explode("/", $cuisines_name_all);
$facility_name = explode("/", $facility_name_all);

是的我可以返回$facility_name，但$cuisines_name与$facility_name的内容相同$cuisines_name应该没有任何内容

因为我需要返回$cuisines_name和$facility_name来从数据库中获取新数据。

如果内爆-没有退出，你知道如何区分数据吗？

Answer 1

这就是你在寻找什么？

情景1

$cuisines_category = "Breakfast/Cake - Accept voucher/New Restaurant";

$split = array_map('trim', explode("-", $cuisines_category));

$cuisines_name_all = (count($split) > 1 ) ? $split[0] : 0;
$facility_name_all = (count($split) > 1 ) ? $split[1] : $split[0];

$cuisines_name = explode("/", $cuisines_name_all);
$facility_name = explode("/", $facility_name_all);

<强>输出

cuisines_name: Array ( [0] => Breakfast [1] => Cake )

facility_name: Array ( [0] => Accept voucher [1] => New Restaurant )

场景2

$cuisines_category = "Accept voucher/New Restaurant";

$split = array_map('trim', explode("-", $cuisines_category));

$cuisines_name_all = (count($split) > 1 ) ? $split[0] : 0;
$facility_name_all = (count($split) > 1 ) ? $split[1] : $split[0];

$cuisines_name = explode("/", $cuisines_name_all);
$facility_name = explode("/", $facility_name_all);

<强>输出

cuisines_name: Array ( [0] => 0 )

facility_name: Array ( [0] => Accept voucher [1] => New Restaurant )

如何在codeginter中挖掘数据

1 个答案: