Question

我正试图找到一种方法来通过以下测试，但我最终仍然在循环中使用循环，这是非常糟糕的。有人可以帮忙吗？这是测试：

require 'spec_helper'

describe Promotion_Check do

  let(:check) { Promotion_Check.new rules_list }
  let(:item_rule) { {rule_type: "item", item_code: 1, number_of_items: 2, new_item_price: 8.50} }
  let(:total_rule)  { {rule_type: "total", total_price_break: 60.00, discount_percentage: 10} }
  let(:rules_list) { [ 1 => item_rule, 2 => total_rule ] }

  describe "#applicable_item_rules" do
    it "finds the rules that apply to the baskets items" do
      item_code = 1
      count = 2
      expect(check.applicable_item_rules(item_code, count)).to eq [item_rule]
    end
  end
end

基本上，我想搜索像这样的哈希数组：

rules_list = [ 1 => {rule_type: "item", item_code: 1, number_of_items: 2, new_item_price: 8.50}, 2 => {rule_type: "item", item_code: 2, number_of_items: 4, new_item_price: 7.50}]

对于具有匹配值的任何内容：item_code和：number_of_items并将该值推送到数组中。

感谢您的帮助

Answer 1

因为Ruby很有帮助

rules_list = [
  1 => {rule_type: "item", item_code: 1, number_of_items: 2, new_item_price: 8.50},
  2 => {rule_type: "item", item_code: 2, number_of_items: 4, new_item_price: 7.50}
]

最终成为：

 => [{
  1=>{:rule_type=>"item", :item_code=>1, :number_of_items=>2, :new_item_price=>8.5},
  2=>{:rule_type=>"item", :item_code=>2, :number_of_items=>4, :new_item_price=>7.5}
}]

这是一个长度为1的数组，包含一个长度为2的散列。你最好这样做：

rules_list = [
  {rule_type: "item", item_code: 1, number_of_items: 2, new_item_price: 8.50},
  {rule_type: "item", item_code: 2, number_of_items: 4, new_item_price: 7.50}
]

并像这样查询：

rules_list.select { |rule| rule[:item_code] == 1 && rule[:number_of_items] == 2 }

 => [{:rule_type=>"item", :item_code=>1, :number_of_items=>2, :new_item_price=>8.5}]

使用散列数组搜索特定值

1 个答案: