案例:我希望在合并对象后得到映射到数据库端默认值的列的字段值。
表格
CREATE TABLE IF NOT EXISTS `db`.`OBJECT` (
`OBJECT_ID` INT NOT NULL AUTO_INCREMENT,
`NAME` VARCHAR(64) NULL,
`CREATED_ON` DATETIME NULL DEFAULT CURRENT_TIMESTAMP,
`EDITED_ON` DATETIME NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP
)
类别:
@Entity
@Table(name="OBJECT")
public class SomeObject {
private int id;
private String name;
private Timestamp createdOn;
private Timestamp editedOn;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ID")
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
@Column(name = "NAME")
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Column(name = "CREATED_ON", insertable = false, updatable = false)
public Timestamp getCreatedOn() {
return createdOn;
}
public void setCreatedOn(Timestamp createdOn) {
this.createdOn = createdOn;
}
@Column(name = "EDITED_ON", insertable = false, updatable = false)
public Timestamp getEditedOn() {
return editedOn;
}
public void setEditedOn(Timestamp editedOn) {
this.editedOn = editedOn;
}
}
DAO:
@Transactional
public class ObjectDAO {
@PersistenceContext
private EntityManager entityManager;
public someObject merge(someObject someObject) {
return entityManager.merge(someObject);
}
}
我想做什么:
SomeObject someObject = new SomeObject();
someObject.setName("name");
SomeObject insertedObject = objectDAO.merge(someObject);
System.out.println(insertedObject.getId());
System.out.println(insertedObject.getEditedOn());
结果: 对象插入数据库,所有默认值都正确生成。
问题: 为什么第二个println打印为null,但是第一个println打印出插入数据库的Id的正确值?
答案 0 :(得分:1)
经过更多研究后,我发现如果我使用默认数据库值,则无法在合并返回的实体中使用它们。就那么简单。我更改了apporach并使用@PrePersist
和@PreUpdate
注释。这应该是这样的:
@Entity
@Table(name="OBJECT")
public class SomeObject {
private int id;
private String name;
private Timestamp createdOn;
private Timestamp editedOn;
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "ID")
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
@Column(name = "NAME")
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Column(name = "CREATED_ON")
public Timestamp getCreatedOn() {
return createdOn;
}
public void setCreatedOn(Timestamp createdOn) {
this.createdOn = createdOn;
}
@Column(name = "EDITED_ON")
public Timestamp getEditedOn() {
return editedOn;
}
public void setEditedOn(Timestamp editedOn) {
this.editedOn = editedOn;
}
@PrePersist
public void setDates() {
createdOn = LocalDateTime.now();
editedOn = LocalDateTime.now();
}
@PreUpdate
public void setEditedOn() {
editedOn = LocalDateTime.now();
}
}
为什么正确的id在返回的实体中?因为它实际上是由Hibernate生成的@GeneratedValue(strategy = GenerationType.IDENTITY)
答案 1 :(得分:0)
尝试在合并后提交,因为我认为这还没有在数据库中hibernate仍然将其保留在内存中
答案 2 :(得分:0)
在执行此行之前:
的System.out.println(insertedObject.getEditedOn());
您必须致电:entityManager.flush();