我是初学程序员。我正在尝试构建一个PHP搜索引擎，可以将用户发布的搜索词插入到MySQL的另一个表中。
此搜索引擎代码搜索数据库，而不将搜索词插入表中。它运作得很好：
<?php
include ("dbconnect.php");
$searchtext = trim(mysqli_real_escape_string($con,$_GET['search']));
$searchbutton = ($_GET['submit']);
$sql = "SELECT * FROM beverage_db WHERE name LIKE '%".$searchtext."%' ORDER BY name";
$query = mysqli_query($con, $sql);
if (mysqli_num_rows($query)>0) {
$results = mysqli_fetch_assoc($query);
do {
echo '<div>'.$results["name"].'</div>';
}while ($results=mysqli_fetch_assoc($query));
}else {
$searchbit = explode("", $_GET['search']);
foreach ($searchbit as $value) {
$metabits = ($value);
$sql = "SELECT * FROM beverage_db WHERE name LIKE '%".$metabits."%' ORDER BY name";
$query = mysqli_query($con, $sql);
$results = mysqli_fetch_assoc($query);
do {
}while ($results=mysqli_fetch_assoc($query));
}
}
?>
现在，当我尝试输入INSERT INTO函数时，它不会将搜索词输入数据库。这是我的尝试：
include ("dbconnect.php");
$searchtext = trim(mysqli_real_escape_string($con,$_GET['search']));
$searchbutton = ($_GET['submit']);
$sql = "SELECT * FROM beverage_db WHERE name LIKE '%".$searchtext."%' ORDER BY name;
INSERT INTO words (words_used) VALUES ('".mysqli_real_escape_string($con, $_GET['search'])."')";
$query = mysqli_query($con, $sql);
if (mysqli_num_rows($query)>0) {
$results = mysqli_fetch_assoc($query);
do {
echo '<div>'.$results["name"].'</div>';
}while ($results=mysqli_fetch_assoc($query));
}else {
$searchbit = explode("", $_GET['search']);
foreach ($searchbit as $value) {
$metabits = ($value);
$sql = "SELECT * FROM beverage_db WHERE name LIKE '%".$metabits."%' ORDER BY name;
INSERT INTO words (words_used) VALUES ('".mysqli_real_escape_string($con, $_GET['search'])."')";
$query = mysqli_query($con, $sql);
$results = mysqli_fetch_assoc($query);
do {
}while ($results=mysqli_fetch_assoc($query));
}
}
?>
不确定是使用正确的功能，还是正确编写代码。
请帮忙