Question

我试图将值从jQuery传递给PHP。这是我的代码，

jQuery功能：

$(document).ready(function () {
        $("#contact_form").submit(function () {
            var RequesterName = $("#RequesterName").val(); 
            var Requestoremail = $("#Requestoremail").val();
            var Subject = '[Request] Mail Subject';
            $.ajax({
                type: 'post',
                dataType: 'json', 
                url: 'sendmail.php',
                data: { RequesterName_val: RequesterName, Requestoremail_val: Requestoremail, Subject_val: Subject },
                success: function (data) {
                    alert('Mail Sent Successsfully');
                }
            });
        });
    })

和PHP：

<?php
    $to = $_POST['RequesterName_val'];
    $subject = $_POST['Subject_val'];
    $RequesterName = $_POST['RequesterName_val'];
    $Requestoremail = $_POST['Requestoremail_val'];

     $message = "RequesterName:".$RequesterName."   , Requestoremail:".$Requestoremail."    ";

                $headers = "MIME-Version: 1.0" . "\r\n";
                $headers .= "Content-type:text/html;charset=UTF-8" . "\r\n";

                // More headers
                $headers .= 'From: <'.$Requestoremail.'>' . "\r\n";
                $headers .= "Reply-To: '.$Requestoremail.'\r\n";

                 if (mail($to,$subject,$message,$headers)) {
                        echo "Success";
                 } else {
                             echo "Error";
                 }

      die();

?>

似乎邮件是从php触发但是我没有得到回复并且“邮件已成功发送”未在jQuery中显示？如何获得邮件触发器成功和失败的响应？

Answer 1

您的$.ajax调用表示响应应为JSON，但您只是返回纯文本。当jQuery尝试解析JSON时出错，它不会调用success:回调。

您可以更正PHP，以便返回JSON：

echo json_encode(mail($to,$subject,$message,$headers));
die();

然后在success函数中写下：

success: function(data) {
    if (data) {
        alert('Mail sent successfully');
    } else {
        alert('Mail not sent');
    }
}

或者您可以更改$.ajax来电使用dataType: 'text'，回调将是：

success: function(data) {
    if (data == 'Success') {
        alert('Mail sent successfully');
    } else {
        alert('Mail not sent');
    }
}

如何使用jQuery将值从html页面传递给PHP并获得响应？

1 个答案: