我的where子句与我想要的相反

Question

这是我的查询。

select sp.name, spi.sku, sum(spi.price), count(sp.name), spi.in_stock, spi.price, sp.is_published, spi.is_reorderable
from shop_product_category spc
inner join shop_product_category_xref spcx
on spc.shop_product_category_id = spcx.shop_product_category_id
inner join shop_product sp
on sp.shop_product_id = spcx.shop_product_id
inner join shop_product_item spi
on spi.shop_product_id = sp.shop_product_id
inner join shop_order_item soi
on spi.shop_product_item_id = soi.shop_product_item_id
where (spc.shop_product_category_id in (1316))
 and sp.is_published = 1
group by sp.name
order by count(sp.name) desc

它返回一切就好了除了我希望它返回sp.is_published = 1的行因此where子句。然而，要获得所需的输出，我必须将当前的where子句更改为     sp.is_published <> 1 所以问题是这个，为什么＆lt;＆gt; 1返回带有1的行，= 1返回带有0的行。谢谢

Answer 1

如果sp.is_published = 1是一个字符串，那么您需要将其放入标记IE sp.is_published = '1'