如何在不阻止的情况下在浏览器中打开新标签?

时间:2016-07-19 16:59:31

标签: javascript haxe openfl stencyl

Haxe / OpenFL代码:

import openfl.net.URLRequest;
import openfl.Lib;

Lib.getURL (new URLRequest (url), "_self");  
// Opens the linked document in the same window or tab as it was clicked

Lib.getURL (new URLRequest (url), "_blank"); 
// Opens the linked document in a new window or tab. (this is default)

但是,第二个选项会生成被Chrome阻止的弹出窗口。

如何在不被阻止的情况下打开另一个标签中的链接?

使用Javascript工作:

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1">

<title>OpenNewTab</title>

<meta id="viewport" name="viewport" content="width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=no" />
<meta name="apple-mobile-web-app-capable" content="yes">

</head>
<body>  

<center>
    <canvas id="myCanvas" width="200" height="200" style="border-style: solid; border-width: 1px"> </canvas>
</center>

<script>   

    var canvas;
    var linkURL = "http://www.google.com";        

    createLink();

    function createLink() {

        canvas = document.getElementById("myCanvas");           
        canvas.addEventListener("click", Link_click, false);

    }

    function Link_click(e) {

         window.open(linkURL,'_blank'); 

    }     
</script>

</body>
</html>

P.s:我使用Stencyl和HTML / JavaScript。

2 个答案:

答案 0 :(得分:0)

我相信如果从用户触发的事件(如指针向下,单击)打开弹出窗口,则弹出窗口阻止程序不应阻止打开它。

  

注意:我个人觉得开发人员决定如何打开一个窗口,为什么不让用户自己决定呢?

答案 1 :(得分:0)

虽然我找不到更好的解决方案,但我会用它:

  html_message = UserMailer.welcome_email(@user).message

  some_api.send_email(from, to, subject, html_message)