Question

你好，在我的项目中，我创建了一个名为＆＃34的对象类;程序＆＃34;有许多值，例如一个名为＆＃34;类别的数组。＆＃34;所有程序都由ListView显示，并在布局中设置了类别Spinner（目的是使用匹配的类别对程序进行分类）。

我有这段代码：

final ArrayAdapter spinnerAdapter =  new ArrayAdapter(getActivity(), R.layout.layout_spinner, MainActivity.categories); //MainActivity.categories is an array filled with strings

spinner.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
    @Override
    public void onItemSelected(AdapterView<?> parent, View view, int position, long id) {

        String text = spinner.getSelectedItem().toString();
        listAdapter.getFilter().filter(text);
        listAdapter.notifyDataSetChanged();
    }

Program.java

public class Program {

    public String programName;
    public ArrayList<String> categories;

     .....

    public ArrayList<String> getCategories () {
        return categories;
    }

    public String toString() {
        return programName;
    }
}

但这仅根据列表中的文字进行过滤，如何通过程序列表中的Category变量对其进行过滤？

Answer 1

那么，

首先来看看这里并了解一下过滤：

Adapter filtering android

接下来，我认为在您的情况下，您必须执行以下操作：

@Override
protected FilterResults performFiltering(CharSequence constraint) {
     FilterResults results = new FilterResults();
    // We implement here the filter logic
    if (constraint == null || constraint.length() == 0) {
        // No filter implemented we return all the list
         results.values = yourList;
         results.count = yourList.size();
    }
    else {
    // We perform filtering operation
    List<Program> finalList = new ArrayList<Program>();
    //here think of something regarding the upper and lower cases.
    for (Program p : yourList) {            
        if(p.getCategories().
              contains(constraint.toString()))
         finalList.add(p);
    }

     results.values = finalList;
     results.count =  finalList.size();
   }
   return results;
}

使用Spinner按对象内的值过滤对象的ListView

1 个答案: