SPServices多个列表相同的站点

时间:2016-07-19 14:25:21

标签: javascript spservices

使用波纹管代码我只能获得一个列表。 但我有两个列表(两个列表中的索引号相同)如何在一个站点中获得两个列表?



<script type="text/javascript" src="filelink/jquery-1.6.1.min.js"></script>
<script type="text/javascript" src="filelink/jquery.SPServices-0.6.2.min.js"></script>
<script language="javascript" type="text/javascript">

$(document).ready(function() {
  $().SPServices({
    operation: "GetListItems",
    async: false,
    listName: "Announcements",
    CAMLViewFields: "<ViewFields><FieldRef Name='Title' /></ViewFields>",
    completefunc: function (xData, Status) {
      $(xData.responseXML).SPFilterNode("z:row").each(function() {
        var liHtml = "<li>" + $(this).attr("ows_Title") + "</li>";
        $("#tasksUL").append(liHtml);
      });
    }
  });
});
</script>
<ul id="tasksUL"/>
&#13;
&#13;
&#13;

1 个答案:

答案 0 :(得分:0)

您只需添加另一个$().SPServices({}); GetListItems操作,并将其附加到其他结果中。

&#13;
&#13;
<script type="text/javascript" src="filelink/jquery-1.6.1.min.js"></script>
<script type="text/javascript" src="filelink/jquery.SPServices-0.6.2.min.js"></script>
<script language="javascript" type="text/javascript">

$(document).ready(function() {
  $().SPServices({
    operation: "GetListItems",
    async: false,
    listName: "Announcements",
    CAMLViewFields: "<ViewFields><FieldRef Name='Title' /></ViewFields>",
    completefunc: function (xData, Status) {
      $(xData.responseXML).SPFilterNode("z:row").each(function() {
        var liHtml = "<li>" + $(this).attr("ows_Title") + "</li>";
        $("#tasksUL").append(liHtml);
      });
    }
  });
  $().SPServices({
    operation: "GetListItems",
    async: false,
    listName: "Second List",
    CAMLViewFields: "<ViewFields><FieldRef Name='Title' /></ViewFields>",
    completefunc: function (xData, Status) {
      $(xData.responseXML).SPFilterNode("z:row").each(function() {
        var liHtml = "<li>" + $(this).attr("ows_Title") + "</li>";
        $("#tasksUL").append(liHtml);
      });
    }
  });
});
</script>
<ul id="tasksUL"/>
&#13;
&#13;
&#13;