此SwipeListView
应该能够根据notification
属性呈现2 +种不同的行:
true
用于通知false
适用于常规商品假设两种类型的行完全不同。我要解决的问题是如何使用允许向右和向左滑动行的SwipeListView
和SwipeRow
元素来渲染此类列表,而不是标准ListView
。
我总是遇到renderRow()
和renderHiddenRow()
方法的问题,这些方法拒绝接受renderRow(data, secId, rowId, rowMap)
返回的内容。
示例app:
import React, { Component } from 'react';
import { AppRegistry, StyleSheet, Text, View, ListView } from 'react-native';
import { SwipeListView, SwipeRow } from 'react-native-swipe-list-view'
var data = [ { id:0, notification: true, },{ id:1, notification: false, },{ id:2, notification: false, } ];
class SampleApp extends Component {
renderRow(data, secId, rowId, rowMap) {
var notificationRow = <SwipeRow disableRightSwipe={false} disableLeftSwipe={false} leftOpenValue={100} rightOpenValue={-100}>
<View style={{flexDirection:'row',justifyContent:'space-between',alignItems:'center', left:0, right:0, paddingVertical:50,borderWidth:1, backgroundColor:'red'}}>
<Text>Accept</Text><Text>Reject</Text>
</View>
<View>
<Text style={{left:0, right:0, paddingVertical:50,borderWidth:1, backgroundColor:'green'}}>Notification</Text>
</View>
</SwipeRow>;
var contentRow = <SwipeRow disableRightSwipe={true} disableLeftSwipe={false} leftOpenValue={100} rightOpenValue={-100}>
<View style={{flexDirection:'row',justifyContent:'space-between',alignItems:'center', left:0, right:0, paddingVertical:50,borderWidth:1, backgroundColor:'red'}}>
<Text>Edit</Text><Text>Delete</Text>
</View>
<View>
<Text style={{left:0, right:0, paddingVertical:50,borderWidth:1, backgroundColor:'blue'}}>Row item</Text>
</View>
</SwipeRow>;
if (data.notification) {
return ({notificationRow});
} else {
return ({contentRow});
}
}
render() {
var ds = new ListView.DataSource({ rowHasChanged: (row1, row2) => row1 !== row2 });
return (
<SwipeListView
dataSource={ds.cloneWithRows(data)}
renderRow={ (data, secId, rowId, rowMap) => {this.renderRow(data, secId, rowId, rowMap);}}
/>
);
}
}
AppRegistry.registerComponent('SampleApp', () => SampleApp);
最常见的错误:
SwipeListView.js:renderRow:67:undefined不是对象(评估 'Component.type')
答案 0 :(得分:1)
看起来return
方法中缺少的部分是renderRow()
。 renderRow={ (data, secId, rowId, rowMap) => {return this.renderRow(data, secId, rowId, rowMap);}}