Question

嗨我想在从另一个表中插入表格时填充自动增量列的值。下面是查询即时使用，它抛出错误

create table test12
(
Id int,
name varchar(255),
dept varchar(255)
)

insert into test12 values(1,'f','cs'),(2,'b','cse'),(3,'c','cs'),(4,'d','cse'),(5,'e','cs'),(6,'f',null)

select * from test12                                                            

create table test34
(
seq int identity(1,1) not null,
name varchar(255) not null,
dept varchar(255) default('cs')
)
insert into test34(seq,name,dept) values 
(1,(select name from test12),
(select case when dept='cse' then 'Y' else 'N' end as dept from test12))

请告诉我这是什么错误

Answer 1

你不需要为Identity列赋值，它是自动添加的，只需将标识列表单插入为：

INSERT INTO test34 (name, dept) 
SELECT 
    name,
    CASE WHEN dept = 'cse' THEN 'Y' ELSE 'N' END AS dept 
FROM test12

如果您确实想手动添加身份值，请尝试以下SET语句。

SET IDENTITY_INSERT test34 ON;

INSERT INTO test34 (seq, name, dept) 
SELECT 
    ID
    name,
    CASE WHEN dept = 'cse' THEN 'Y' ELSE 'N' END AS dept 
FROM test12

SET IDENTITY_INSERT test34 OFF;

Answer 2

您可以转为ON或OFF IDENTITY_INSERT

SET IDENTITY_INSERT test34 ON

insert into test34(seq,name,dept) values 
(1,(select name from test12),
(select case when dept='cse' then 'Y' else 'N' end as dept from test12))

SET IDENTITY_INSERT test34 OFF

Answer 3

无需自动为自动增量列插入值，它将生成值。

insert into test34(name,dept) 
select name, Case when dept='cse' then 'Y' else 'N' end as dept from test12

sql查询将值插入自动增量列

3 个答案: