当作为参数传递给方法时,ViewModel不会从POST表单绑定

时间:2010-10-02 13:26:42

标签: asp.net-mvc-2 mode

我是asp.net mvc的新手,但我在各处都仔细搜索过这个主题。

我有一个名为PictureViewModel的ViewModel类,它是EditorTemplate视图继承的类:     <%@ Control Language =“C#”Inherits =“System.Web.Mvc.ViewUserControl”%>

<div class="editor-label"><%: Html.LabelFor(m=>m.Name) %></div> 
<div class="editor-field"><%: Html.TextBox("form.Name") %></div> 

<div class="editor-label"><%: Html.LabelFor(m=>m.Description) %></div> 
<div class="editor-field"><%: Html.TextArea("form.Description") %></div> 

<% Html.RenderAction("SelectCategory", "Category"); %>

<div class="editor-label"><label for="thumbFile">Thumb</label></div> 
<div class="editor-field"><input id="thumbFile" name="thumbFile" type="file"/></div> 

<div class="editor-label"><label for="fullFile">Full</label></div> 
<div class="editor-field"><input id="fullFile" name="fullFile" type="file"/></div> 

此外,我还有文件字段和所有发布到自身的文件

<%@ Page Title="" Language="C#" MasterPageFile="/Views/Shared/Site_Table.Master"
 Inherits="System.Web.Mvc.ViewPage<MvcApplicationVelarPolya.Areas.Admin.Models.PictureViewModel>" %>

<asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server">
    Create
</asp:Content>

<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server">

    <h2>Create</h2>

    <%
  using (Html.BeginForm("create", "Pictures", FormMethod.Post, new {enctype="multipart/form-data"})) 
   {%> 

    <%: Html.EditorForModel() %>

    <input type="submit" name="Create" />

<% }%>

</asp:Content>

以下是专门用于处理提交的代码:

    [HttpPost]
    public ActionResult Create([Bind(Prefix="form")] PictureViewModel pm)
    {
        try
        {
            var p = new PictureViewModel();
            UpdateModel(p, "",new[] {"Name", "Description"});
            ViewData["name"] = Request.Files[0].FileName;
            return View("New", p);
        }
        catch
        {
            return View();
        }
    }

添加前缀,也不使用FormCollection和UpdateModel都无济于事。 我非常感谢任何帮助! 安德鲁。

哦,是的,viewdata正确填充了文件名!

这也行不通         [HttpPost]         public ActionResult Create(FormCollection fc / [Bind(Prefix =“form”)] PictureViewModel pm /)         {             尝试             {                 var p = new PictureViewModel();                 UpdateModel(p,“form”,new [] {“Name”,“Description”});                 ViewData [“name”] = Request.Files [0] .FileName;                 // TODO:在这里添加插入逻辑                 return View(“New”,p);                 return RedirectToAction(“Index”);             }             抓住             {                 return View();             }         }

这段代码

        foreach (var k in fc)
        {
            Debug.WriteLine(k.ToString());
        }

正在制作

form.Name
form.Description
CategoryID
Create

1 个答案:

答案 0 :(得分:1)

在你的编辑器模板中,你应该使用强类型助手(TextBoxForTextAreaFor),你可以摆脱魔术字符串和前缀:

<div class="editor-label"><%: Html.LabelFor(m => m.Name) %></div> 
<div class="editor-field"><%: Html.TextBoxFor(m => m.Name) %></div> 

<div class="editor-label"><%: Html.LabelFor(m => m.Description) %></div> 
<div class="editor-field"><%: Html.TextAreaFor(m => m.Description) %></div> 

<% Html.RenderAction("SelectCategory", "Category"); %>

<div class="editor-label"><label for="thumbFile">Thumb</label></div> 
<div class="editor-field"><input id="thumbFile" name="thumbFile" type="file"/></div> 

<div class="editor-label"><label for="fullFile">Full</label></div> 
<div class="editor-field"><input id="fullFile" name="fullFile" type="file"/></div> 

要处理上传的文件,您可以将它们添加为视图模型属性或操作参数:

public class PictureViewModel
{
    public string Name { get; set; }
    public string Description { get; set; }
    public HttpPostedFileBase ThumbFile { get; set; }
    public HttpPostedFileBase FullFile { get; set; }
}

...

[HttpPost]
public ActionResult Create(PictureViewModel pm)
{
    // Normally the pm variable should be fully 
    // initialized here from the POST request and you can use it directly
    // No need to call UpdateModel
    return View("New", pm);
}