当我尝试使用php将数据从html表单发送到数据库时，我不断获得error unexpected ; in line 6。我似乎无法找到确切的原因。
这是send.php的代码：
<?php
//Connecting to sql db.
$connect = mysqli_connect("host","user","password","database");
//Sending form data to sql db.
mysqli_query($connect,"INSERT INTO sw5_green (firstname_r, lastname_r, vid, occupation, address, firstname_s, lastname_s, country, amount, currency)
VALUES ('$_POST[post_firstname_r]', '$_POST[post_lastname_r]', '$_POST[post_vid]', '$_POST[post_occupation]', '$_POST[post_address]', '$_POST[post_firstname_s]', '$_POST[post_lastname_s]', '$_POST[post_country]', '$_POST[post_amount]', '$_POST[post_currency]')";
?>
答案 0 :(得分：1)
您在语句末尾缺少)。在)之前放置;。
试试吧，
mysqli_query($connect,"INSERT INTO sw5_green (firstname_r, lastname_r, vid, occupation, address, firstname_s, lastname_s, country, amount, currency)
VALUES ('$_POST[post_firstname_r]', '$_POST[post_lastname_r]', '$_POST[post_vid]', '$_POST[post_occupation]', '$_POST[post_address]', '$_POST[post_firstname_s]', '$_POST[post_lastname_s]', '$_POST[post_country]', '$_POST[post_amount]', '$_POST[post_currency]')");
答案 1 :(得分：0)
你缺席了）
使用此
替换您的代码mysqli_query($connect,"INSERT INTO sw5_green (firstname_r, lastname_r, vid, occupation, address, firstname_s, lastname_s, country, amount, currency)
VALUES ('$_POST[post_firstname_r]', '$_POST[post_lastname_r]', '$_POST[post_vid]', '$_POST[post_occupation]', '$_POST[post_address]', '$_POST[post_firstname_s]', '$_POST[post_lastname_s]', '$_POST[post_country]', '$_POST[post_amount]', '$_POST[post_currency]'))";
答案 2 :(得分：0)
错误的语法
'$ _ POST [post_firstname_r]'应为$ _POST ['post_firstname_r']
保存前始终转义数据。