Question

我将数据库中的值提取到.gitignore，但是我想将Spinner中的选定项插入到数据库中，我该怎么做？

我使用了两个Spinner，并且Spinners所选项都应该插入到数据库中。

如何在Spinner's中插入项目以及我需要做什么？

活动类： -

PHP

Answer 1

如果要在sqlite中存储微调器选定项，请遵循此代码 1.创建一个本地数据库 2.在您的活动中插入选定的值，如下所示。

LocalDatabase：

public class SpinnerDatabaseHandler extends SQLiteOpenHelper {
private static final int DATABASE_VERSION = 1;

// Database Name
private static final String DATABASE_NAME = "spinnerModule";

// Labels table name
private static final String TABLE_LABELS = "spinner";

// Labels Table Columns names
private static final String KEY_ID = "id";
private static final String KEY_SPINONE = "spinone";
private static final String KEY_SPINTWO = "spintwo";
SQLiteDatabase db;

public LoginDatabaseHandler(Context context) {
    super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
    // Category table create query
    String CREATE_CATEGORIES_TABLE = "CREATE TABLE " + TABLE_LABELS + "("
            + KEY_ID + " INTEGER PRIMARY KEY,"
            + KEY_SPINONE + " TEXT,"           

            + KEY_SPINTWO + " TEXT" + ");";


    db.execSQL(CREATE_CATEGORIES_TABLE);
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
    // Drop older table if existed
    db.execSQL("DROP TABLE IF EXISTS " + TABLE_LABELS);

    // Create tables again
    onCreate(db);
}
public void insertLabel(String spinone,String spintwo){
    SQLiteDatabase db = this.getWritableDatabase();

    ContentValues values = new ContentValues();
    //values.put(KEY_ID,id);
    values.put(KEY_SPINONE,spinone);
    values.put(KEY_SPINTWO,spintwo);

    // Inserting Row
    db.insert(TABLE_LABELS, null, values);
    db.close(); // Closing database connection
}

}

将值从您的活动插入sqlite中 1.将主要活动中的sqlite数据库初始化为

SpinnerDatabaseHandler db=new SpinnerDatabaseHandler(getApplicationContext);

2.之后添加这些代码

 String firstspin=spinner1.getSelectedItem.toString();
 String secondspin=spinner2.getSelectedItem.toString();
 db.insertlabel(firstspin,secondspin);

Answer 2

我假设您有“保存/确定”按钮，用于将微调器选定项插入数据库。

获取微调器选定的项目值

String spinner1SlctdVal = spinner1.getSelectedItem().toString(); // Course spinner
String spinner2SlctdVal = spinner2.getSelectedItem().toString(); // Username spinner

对于PHP中的插入微调器选定项

you have to call PHP web-service using AsyncTask or other methods.

当用户点击代码下面的“保存/确定”按钮时，从两个微调器中选择值后。

保存/确定按钮代码单击：

mBtnSave.setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View v) {

        String spinner1SlctdVal = spinner1.getSelectedItem().toString();
        String spinner2SlctdVal = spinner2.getSelectedItem().toString();

        // Insert spinner selected values in database
        SQLiteDatabase database = this.getWritableDatabase();
        ContentValues values = new ContentValues();
        values.put("course", spinner1SlctdVal); // "course" is column name of your table
        values.put("username", spinner2SlctdVal); // "username" is column name of your table
        database.insert("users", null, values); // "users" is your table name
        database.close();

        // Call AsynTask or other method for call web-service (for insert selected values into PHP server)
    }
});

Answer 3

插入值的Php文件：

<?php
     $_SERVER['REQUEST_METHOD']=='POST';
     define('HOST','hostname');
     define('USER','username');
     define('PASS','password');
     define('DB','databasename'); 
     $con = mysqli_connect(HOST,USER,PASS,DB) or die('Unable to Connect'); 

    $firstspin=$_POST['lspinone'];
    $secondspin=$_POST['lspintwo'];



     $query = "INSERT INTO `spinnertable` (`spione`, `spintwo`) VALUES ('".$firstspin."', '".$secondspin."')";
     $inserted = @mysqli_query($con, $query);
     if($inserted == 1 ){
                    echo "success";
                }else{
                    echo "user exist already";
                }
                mysqli_close($con);

?>

将值从android传递给php的代码：

package nidhinkumar.gridcam.logindetails;

public class MainPAge extends AppCompatActivity{
private static final String LOGINALL_URL =   "http://smpleuser.com/07032016/php/nameofphpfile.php";


@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.spinnerpage);
    String spinone=spinner1.getSelectedItem.toString();
    Stirng spintwo=spinner2.getSelectedItem.toString();

    // Call AsyncTask for send selected value to PHP server. 
    userSpinnr(spinone, spintwo);
} 



private void userSpinnr(final String lspinone, final String lspintwo) {
    rando=(int)(Math.random()*10);
    class LoginSpinners extends AsyncTask<String,Void,String> {
        ProgressDialog loading;


        @Override
        protected void onPreExecute() {
            super.onPreExecute();

            loading = ProgressDialog.show(LoginPage.this, "Do you know?", "", true, false);

        }

        @Override
        protected void onPostExecute(String s) {
            super.onPostExecute(s);
            if(s.equalsIgnoreCase("success")) {

                //do the action what you want
                } catch (SQLException e) {

                }


            }else{                    
                    loading.dismiss();
                } catch (SQLException e) {

                }
            }
        }

        @Override
        protected String doInBackground(String... params) {
            HashMap<String,String> data = new HashMap<>();
            data.put("lspinone",params[0]);
            data.put("lspintwo",params[1]);

            RegisterUserClass ruc = new RegisterUserClass();
            String result = ruc.sendPostRequest(LOGINALL_URL,data);
            return result;
        }
    }
    LoginSpinners ulc = new LoginSpinners();
    ulc.execute(lspinone,lspintwo);

}

}

我如何将微调器选中的项目插入到移动应用程序的mysql数据库中？

3 个答案: