仅当Android中的EditText
不为空时才验证电子邮件格式。如果该字段为空白,则不应检查验证。我在这个场景中没有找到任何对我有用的解决方案。
答案 0 :(得分:1)
试用此代码
final EditText emailEditTxt= (EditText)findViewById(R.id.text);
String emailStr = emailEditTxt.getText().toString().trim();
if(emailStr!=null)
if(emailStr.length()>=1){
String emailPattern = "[a-zA-Z0-9._-]+@[a-z]+\\.+[a-z]+";
if (emailStr .matches(emailPattern))
{
Toast.makeText(getApplicationContext(),"valid email address",Toast.LENGTH_SHORT).show();
}
else
{
Toast.makeText(getApplicationContext(),"Invalid email address", Toast.LENGTH_SHORT).show();
}
}
答案 1 :(得分:1)
试试这个..
boolean flag;
String pass = editText.getText().toString().trim();
if(!pass.equals("")) {
flag = isEmailValid(pass);
}
public static boolean isEmailValid(CharSequence email) {
return Patterns.EMAIL_ADDRESS.matcher(email).matches();
}
并使用flag
值进一步使用
答案 2 :(得分:0)
使用此方法检查电子邮件模式是否有效
public static boolean isEmailValid(CharSequence email) {
return Patterns.EMAIL_ADDRESS.matcher(email).matches();
}
答案 3 :(得分:0)
<强> validateEmail 强>
private boolean validateEmail() {
if (!edemail.getText().toString().trim().isEmpty()&&!ValidationMethod.emailValidation(edemail.getText().toString()))
{
input_layout_email.setError("Invalid Email"); // Your textInput Layout or other set your error on edittext email
requestFocus(edemail);
return false;
}
else {
input_layout_email.setErrorEnabled(false);
}
return true;
}
// if you need requestfocus other wise remove
private void requestFocus(View view) {
if (view.requestFocus()) {
getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_VISIBLE);
}
}
ValidationMethod.java //放入您的项目
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class ValidationMethod {
static Matcher m;
static String emailExpression = "^[\\w\\.-]+@([\\w\\-]+\\.)+[A-Z]{2,20}$";
static Pattern emailPattern = Pattern.compile(emailExpression, Pattern.CASE_INSENSITIVE);
static String passwordExpression ="((?=.*\\d)(?=.*[a-z])(?=.*[A-Z])(?=.*\\W).{8,20})";
static Pattern passwordPattern=Pattern.compile(passwordExpression);
public static boolean emailValidation(String s)
{
if( s == null)
{
return false;
}
else
{
m = emailPattern.matcher(s);
return m.matches();
}
}
public static boolean passwordValidation(String s)
{
if( s == null)
{
return false;
}
else
{
m = passwordPattern.matcher(s);
return m.matches();
}
}
public static boolean emailValidation2(String s)
{
m = emailPattern.matcher(s);
return m.matches();
}
}
答案 4 :(得分:0)
试试这个
<form>
<lable for="userEmail">Email : </label>
<input type="email" id="userEmail" placeholder="johndoe@example.com" required="required">
<form>
答案 5 :(得分:0)
假设你已经像这样声明了EditText。
EditText emailField;
然后在你的方法
emailField = (EditText)view.getViewById(R.id.NAME_OF_FIELD_IN_XML);
if(!TextUtils.isBlank(emailField.getText().toString())){
//validate your email address
}
使用以下链接查看电子邮件验证码。
http://stackoverflow.com/questions/12947620/email-address-validation-in-android-on-edittext
答案 6 :(得分:0)
您可以尝试进行验证。
public boolean Email_validation(String CorpId)
{
String regExpn =
"^(([\\w-]+\\.)+[\\w-]+|([a-zA-Z]{1}|[\\w-]{2,}))@"
+"((([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?"
+"[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\."
+"([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?"
+"[0-9]{1,2}|25[0-5]|2[0-4][0-9])){1}|"
+"([a-zA-Z]+[\\w-]+\\.)+[a-zA-Z]{2,4})$";
CharSequence inputStr = CorpId;
Pattern pattern = Pattern.compile(regExpn, Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(inputStr);
if(matcher.matches())
return true;
else
return false;
}