价值观与R中的水平不匹配

时间:2016-07-19 04:33:57

标签: r dataframe r-factor

给定数据帧的几列是因子水平向量,以其中一个为例:

[4661] 12.7          13.2          10.1          12.3         
[4665] Not Available 12.7          Not Available Not Available
[4669] Not Available Not Available Not Available 11.1         
[4673] 9.9           9             Not Available 9.7          
[4677] 8.9           10.1          11.7          13           
[4681] Not Available 11.5          Not Available Not Available
[4685] 12.3          11.2          Not Available 11.1         
[4689] 10.4          Not Available Not Available Not Available
[4693] 11.5          Not Available Not Available Not Available
[4697] Not Available Not Available 12            Not Available
[4701] Not Available Not Available Not Available Not Available
[4705] Not Available Not Available
106 Levels: 10 10.1 10.2 10.3 10.4 10.5 10.6 10.7 10.8 10.9 ... Not Available

我觉得很烦人,它一直说106级别从10开始然后是10.1,但事实上有很多值低于10,如上面列表所示。

如何解决这个问题,让级别自动匹配所有值?谢谢。

1 个答案:

答案 0 :(得分:1)

您可以使用重新factor -

将订单更改为数字顺序
x <- factor(c(10,10.1,10.2,9,8,1,"Not available"))
levels(x)
#[1] "1"             "10"            "10.1"          "10.2"         
#[5] "8"             "9"             "Not available"


factor(x, levels=levels(x)[order(as.numeric(as.character(levels(x))),na.last=TRUE)])
#[1] 10            10.1          10.2          9             8             1             Not available
#Levels: 1 8 9 10 10.1 10.2 Not available

可以说你应该首先将这些数据用作数字,例如:

as.numeric(as.character(x))
#[1] 10.0 10.1 10.2  9.0  8.0  1.0   NA