package javaapplication1;
import java.io.*;
/**
*
* @author simon
*/
public class Main {
/**
* @param args the command line arguments
*/
public static void main(String[] args) throws IOException {
NotSimple[] objArray;
BufferedReader stdin = new BufferedReader(
new InputStreamReader( System.in ) );
System.out.println( "Enter a number of objects:" );
int size;
size = Integer.parseInt( stdin.readLine() );
//Initialize objArray
objArray = new NotSimple[size];
//TODO: Implement following functions
initializeObj(objArray);
increaseData(objArray);
printObjData(objArray);
//TODO: Explain all outputs of the below function
explainOutputs();
return;
}
//TODO
//initialize every Notsimple object in the array 'a'
//to NotSimple()
//Hint: using the for loop, assign a[i] = new NotSimple();
static void initializeObj(NotSimple[] a){
//TODO: FILL ME
for (int i = 0; i < a.length; i++)
{
a[i] = new NotSimple();
}
}
//TODO:
//Increase the ‘data’ member of every NotSimple object
//in the array ‘a’ by 1
static void increaseData(NotSimple[] a) {
//TODO: FILL ME
for (int i = 0; i < a.length; i++)
{
a[i].setData(a[i].getData()+1);
}
}
//TODO:
//Print the data of every NotSimple object in the array ‘a’
static void printObjData(NotSimple[] a) {
//TODO: FILL ME
for (int i = 0; i < a.length; i++)
{
System.out.println (a[i].getData());
}
}
//TODO explain all the outputs 1a-1f
static void explainOutputs() {
NotSimple nsObj1 = new NotSimple();
//1a
System.out.println( "nsObj1.data is\t" + nsObj1.getData() );
System.out.println( "nsObj1.str is \t" + nsObj1.getStr() );
NotSimple nsObj2 = new NotSimple( 50,
"Another immutable string!" );
//1b
System.out.println( "nsObj2.data is\t" + nsObj2.getData() );
System.out.println( "nsObj2.str is \t" + nsObj2.getStr() );
nsObj2 = nsObj1;
nsObj2.setData(10);
nsObj1.setData(100);
//1c
System.out.println( "nsObj2.data is\t" + nsObj2.getData() );
System.out.println( "nsObj2.str is \t" + nsObj2.getStr() );
nsObj1 = new NotSimple();
//1d
System.out.println( "nsObj1.data is\t" + nsObj1.getData() );
System.out.println( "nsObj1.str is \t" + nsObj1.getStr() );
System.out.println( "nsObj2.data is\t" + nsObj2.getData() );
System.out.println( "nsObj2.str is \t" + nsObj2.getStr() );
nsObj2 = new NotSimple();
//1e
System.out.println( "nsObj2.data is\t" + nsObj2.getData() );
System.out.println( "nsObj2.str is \t" + nsObj2.getStr() );
nsObj2.setData(10);
//1f
System.out.println( "nsObj1.data is\t" + nsObj1.getData() );
System.out.println( "nsObj1.str is \t" + nsObj1.getStr() );
System.out.println( "nsObj2.data is\t" + nsObj2.getData() );
System.out.println( "nsObj2.str is \t" + nsObj2.getStr() );
}
}
class NotSimple
{
NotSimple()
{
data = 5;
str = new String( "Initialized!" );
}
NotSimple( int i, String str1 )
{
data = i;
str = str1;
}
void setData( int i )
{
data = i;
return;
}
int getData()
{
return data;
}
void setStr( String str1)
{
str = str1;
return;
}
String getStr()
{
return str;
}
private int data;
private String str;
}
我想在数组中添加1,但它不起作用。我收到以下编译错误:
operator ++ cannot be applied to javaapplication1.NotSimple
答案 0 :(得分:2)
使用
for (int i = 0; i < a.length; i++)
{
a[i].setData(a[i].getData()+1);
}
由于Java不支持运算符重载,因此您需要检索旧值(即getData()调用),向其中添加1,并将其设置为新值(即setData()调用)。
答案 1 :(得分:0)
NotSimple类是什么样的?
NotSimple是一个可以递增的数字类型吗?
答案 2 :(得分:0)
如果NotSimple有一个名为'data'的字段,那么将[i] ++替换为[i] .data ++