Question

我想在Spring MVC ModelAttribute（Person）和Jackson的帮助下，从html表单创建一个xml。

形式：

....
<input name="name"/>
<input name="birthday"/>
<input name="address.street/>
<input name="address.city/>
....

POJO：

@JacksonXmlRootElement(localName = "person")
@JsonInclude(Include.NON_DEFAULT)
public class Person implements Serializable {
    @JsonIgnore
    private Long id;
    @JacksonXmlProperty(localName = "name")
    private String name;
    @JacksonXmlProperty(localName = "email")
    private String email;
    @JacksonXmlProperty(localName = "address")
    private Address address;
    private String birthday;

//getter and setter

}

@JsonInclude(Include.NON_EMPTY)
public class Address implements Serializable {
    private Long id;
    private String street;
    private String streetNumber;
    private String postalcode;
    private String city;

   //getter and setter
}

在Controller中创建XML：

@RequestMapping("saveperson")
public String savePerson(@ModelAttribute final Person person, final ModelMap model) {
    final ObjectMapper xmlMapper = new XmlMapper();
    final String xml = xmlMapper.writeValueAsString(person);
    return "redirect:/listpersons";
}

输出xml：

    <person>
        <name>John</name>
        <email>john@test.com</email>
        <address/>
    </person>

如何从XML中排除空对象？

我尝试将ModelAttribute中的所有空字符串设置为null：

@InitBinder
public void initBinder(WebDataBinder binder) {
    binder.registerCustomEditor(String.class, new StringTrimmerEditor(true));
}

但它不起作用。我也试过了 @JsonInclude（Include.NON_EMPTY）和@JsonInclude（Include.NON_NULL）但它总是包含XML中的空对象。

我的第二个问题是：当我想将地址列表绑定到html表单时。这样做的最佳方式是什么？

....
<input name="name"/>
<input name="birthday"/>
<input name="address1.street/>
<input name="address1.city/>
<input name="address2.street/>
<input name="address2.city/>
....

@JacksonXmlRootElement(localName = "person")
@JsonInclude(Include.NON_DEFAULT)
public class Person implements Serializable {
    @JsonIgnore
    private Long id;
    @JacksonXmlProperty(localName = "name")
    private String name;
    @JacksonXmlProperty(localName = "email")
    private String email;
    @JsonIgnore
    private Address address1;
    @JsonIgnore
    private Address address2;
//add address1 and address2 in the getter or dto for the ModelAttribute?
    @JacksonXmlElementWrapper(localName = "addresses")
    @JacksonXmlProperty(localName = "address")
    private List<Address> address;
    private String birthday;

//getter and setter

}

谢谢！

Answer 1

ChrisIsHere！

我刚刚遇到这个问题，很高兴看到有人提出同样的问题，但很遗憾没有人回应。

经过修改后，我发现了第一个问题的两个可能的解决方案，即不包括XML输出中的空值。

首先在我的模型上加上@JsonInclude(JsonInclude.Include.NON_EMPTY)。所以对你来说，在这种情况下，我怀疑这会起作用：

@JacksonXmlRootElement(localName = "person") 
@JsonInclude(JsonInclude.Include.NON_EMPTY) 
public class Person implements Serializable {
    @JsonIgnore 
    private Long id;
    @JacksonXmlProperty(localName = "name") 
    private String name;
    @JacksonXmlProperty(localName = "email") 
    private String email;
    @JacksonXmlProperty(localName = "address") 
    private Address address;
    private String birthday;

   //getter and setter 
}

这取消了之前的Include.NON_DEFAULT，我希望如果你走这条路，你可以活下去。{/ p>

其次，似乎还有一个我没有使用的替代解决方案，这将让我们直接改变XmlMapper：

XmlMapper xmlMapper = new XmlMapper();
xmlMapper.setSerializationInclusion(JsonInclude.Include.NON_EMPTY);

我希望其中一个有所帮助，迟到十个月。

Jackson xml在序列化时忽略空对象

1 个答案: