Cypher group by subquery语法

Question

我需要在Neo4j上的Cypher中对聚合进行聚合;

match (
  match (w:words) 
  return distinct k.word as word, count(w) as count, count(distinct w.id) as id
  ) as a
return distinct id, count(word), sum(count);

这可能，谷歌建议不是吗？

Answer 1

使用with尝试这样的事情：

match (w:words)
with distinct w.word as word, count(w) as count, count(distinct w.id) as id
return distinct id, count(word), sum(count);