Question

大家好，我如何解析维基百科的描述，我不需要标题或内容我只需要维基页面的简短描述。所以我要解析，但是有一个错误;

private static String url = "https://en.wikipedia.org/w/api.php?action=query&format=json&list=search&srsearch=chocolate";

//names
final String QUERY = "query";
final String LIST = "search";
final String TITLE = "title";
final String SNIPPET = "snippet";

JSONObject searchJson = new JSONObject(searchJsonStr);
JSONObject queryObject = searchJson.getJSONObject(QUERY);
JSONArray searchObject = queryObject.getJSONArray(LIST);
JSONObject titObject = (JSONObject) searchObject.get(0);

String title = titObject.getString(TITLE);
String description = titObject.getString(SNIPPET);

我的错误是;

searchJsonStr无法解析为变量

Answer 1

您收到此错误，因为您的代码中没有名为searchJsonStr的变量。

您需要先检索api请求的JSON内容，然后将其用作变量searchJsonStr。

您可以使用此代码：

String searchJsonStr = null;

URL url = new URL("https://en.wikipedia.org/w/api.php?action=query&format=json&list=search&srsearch=chocolate");

urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setRequestMethod("GET");

int responseCode = urlConnection.getResponseCode();

if (responseCode == HttpsURLConnection.HTTP_OK) {
    InputStream in = new BufferedInputStream(urlConnection.getInputStream());
    searchJsonStr = getStringFromInputStream(in);
} else {
    searchJsonStr = null;
}

来自Wiki的JSon Parse

1 个答案: