将数据从控制器传递到gridview失败

Question

我一直在尝试将一组模型数据从控制器传递到gridview到gridview但是我收到错误：

The "query" property must be an instance of a class that implements the 
QueryInterface e.g. yii\db\Query or its subclasses.

这是控制器代码：

 public function actionAddunits($id){

  $countUnits = Unitslocation::find()->where(['officelocationid'=>$id])->count();
    if(count($countUnits)>0){

   $dataProvider = new ActiveDataProvider([
        'query' =>Unitslocation::find()->where(['officelocationid'=>$id])->all()
    ]);

      return $this->render('assignunits', ['dataProvider'=>$dataProvider]);

    }else{
        return 0;
    }

}

视图（assignunits.php）

<?php
echo GridView::widget([
'dataProvider' => $dataProvider,
'columns' => [
    // ...
    [
        'class' => 'yii\grid\CheckboxColumn',
        // you may configure additional properties here
    ],
],]);

?>

可能出现什么问题？

Answer 1

ActivedataProvider需要query。在您的情况下，您发送query(all())的结果。

删除all()中的query。

$query = Unitslocation::find()->where(['officelocationid'=>$id]);
$dataProvider = new ActiveDataProvider([
    'query' => $query,
]);