Question

我在XML变量中跟随string __MessageIn格式化字符串：

string _MessageIn=
    <?Label TSRAY|RESERVATION|317859|SUCCESS?>
    <Reservation xmlns="reservation.fidelio.2.0" mfShareAction="NA" mfReservationAction="EDIT">
      <HotelReference>
        <hotelCode>TSRAY</hotelCode>
      </HotelReference>
      <confirmationID>Y6Z7TFJDK</confirmationID>
      <reservationID>347557</reservationID>
      <reservationOriginatorCode>JA</reservationOriginatorCode>
      <originalBookingDate>2010-08-16T22:53:23.000</originalBookingDate>
      <StayDateRange timeUnitType="DAY">
        <startTime>2010-08-19T00:00:00.000</startTime>
        <numberOfTimeUnits>3</numberOfTimeUnits>
      </StayDateRange>
      <GuestCounts>
        <GuestCount>
          <ageQualifyingCode>ADULT</ageQualifyingCode>
          <mfCount>2</mfCount>
        </GuestCount>
        <GuestCount>
          <ageQualifyingCode>CHILD</ageQualifyingCode>
          <mfCount>0</mfCount>
        </GuestCount>
      </GuestCounts>
      ...................
     ..................
    </Reservation>

我试图从<hotelCode>TSRAY</hotelCode>获取酒店代码的值，即 TSRAY ，但代码始终在NULL中返回HotelReference。

我尝试了以下代码行：

// query the XML document
XDocument doc = XDocument.Parse(_MessageIn);

var HotelReference = doc.Descendants("HotelReference").Select(x => new { HotelCode = x.Element("hotelCode").Value}).FirstOrDefault();

如何从XML格式string variable上方获取所需的值？

提前致谢！

Answer 1

这是因为命名空间是xml的一部分。

有两种方法可以解决这个问题，要么删除名称空间“reservation.fidelio.2.0”，那么您的代码将无问题地运行。但这可能不太可行。

因此，在执行搜索时，我们必须将命名空间与节点名称一起传递。尝试以下操作，这将解决您的问题。希望这会有所帮助。

        string ns = "reservation.fidelio.2.0";
        string node = "HotelReference";
        string elem = "hotelCode";
        XName xn = XName.Get(node, ns);
        XName xe = XName.Get(elem, ns);
        var HotelReference = doc.Root.Descendants(xn).Select(x => new { HotelCode = x.Element(xe).Value }).FirstOrDefault();

Answer 2

试试这个，

 string _MessageIn="<?Label TSRAY|RESERVATION|317859|SUCCESS?>    <Reservation xmlns='reservation.fidelio.2.0' mfShareAction='NA' mfReservationAction='EDIT'>      <HotelReference>        <hotelCode>TSRAY</hotelCode>      </HotelReference>     <confirmationID>Y6Z7TFJDK</confirmationID>      <reservationID>347557</reservationID>      <reservationOriginatorCode>JA</reservationOriginatorCode>      <originalBookingDate>2010-08-16T22:53:23.000</originalBookingDate>      <StayDateRange timeUnitType='DAY'>        <startTime>2010-08-19T00:00:00.000</startTime>        <numberOfTimeUnits>3</numberOfTimeUnits>      </StayDateRange>      <GuestCounts>        <GuestCount>          <ageQualifyingCode>ADULT</ageQualifyingCode>          <mfCount>2</mfCount>        </GuestCount>        <GuestCount>          <ageQualifyingCode>CHILD</ageQualifyingCode>          <mfCount>0</mfCount>        </GuestCount>      </GuestCounts>      ...................   ..................    </Reservation>";    
                string HotelCode = ""; // you can create HotelCode-Array to store all Hotelcodes
                XmlDocument doc = new XmlDocument();
                doc.LoadXml(_MessageIn);
                XmlNodeList list=doc.GetElementsByTagName("hotelCode");
                foreach (XmlNode node in list)
                {
                    if (node.Name == "hotelCode")
                    {
                        HotelCode=node.InnerText;
                    }
                }

如何从XML格式的字符串中读取任何节点元素的值？

2 个答案: