有没有办法将字符串如“hello \ r \ n \ world”解释为字符串,其中\ r \ n已转换为实际的字面值。
场景是用户键入正则表达式替换表达式并在UI中键入\ r \ n。那个得到了逃脱,但我想从中得到实际的解释字符串。
答案 0 :(得分:2)
我并不直接熟悉一种“简单”的处理方式(即我注意到是否有内置的库可以处理这个)。 但实现此目的的一种方法是阅读有关转义序列的JLS规范并编写单遍解析器,它可以查找和评估每个转义序列。 (检查JLS 3.10.6 Escape Sequences for Character and String Literals)。
现在我知道一个事实,你会很快忘记处理一些奇怪的事情,例如八进制转义是棘手的,因为它允许1,2或3位数,并且在每种情况下都允许不同当它是一个转义时,以及它只是整数时的值。
取示例字符串“\ 431”这是与字符“1”连接的ocal转义符'\ 43',因为八进制转义符的第一个数字是4,因此不能是完整的三位数八进制值在这种情况下,它只允许[0-3]作为第一个数字。
大约一年前,我正在为1.3规范的子集共同编写一个Java编译器,它有转义序列,下面我已经包含了处理转义的代码 - 你实际上应该能够代码字面上的实际情况并包含在Utility类中(如果您觉得有慈善事业可能会信用):
private String processCharEscapes(String strVal) {
// Loop helpers
char[] chrArr = strVal.toCharArray();
StringBuilder strOut = new StringBuilder(strVal.length());
String strEsc = ""; // Escape sequence, string buffer
Character chrBuf = null; // Dangling character buffer
// Control flags
boolean inEscape = false; // In escape?
boolean cbOctal3 = true; // Can be octal 3-digit
// Parse characters
for(char c : chrArr) {
if (!inEscape) {
// Listen for start of escape sequence
if (c == '\\') {
inEscape = true; // Enter escape
strEsc = ""; // Reset escape buffer
chrBuf = null; // Reset dangling character buffer
cbOctal3 = true; // Reset cbOctal3 flag
} else {
strOut.append(c); // Save to output
}
} else {
// Determine escape termination
if (strEsc.length() == 0) { // First character
if (c >= 48 && c <= 55) { // c is a digit [0-7]
if (c > 51) { // c is a digit [4-7]
cbOctal3 = false;
}
strEsc += c; // Save to buffer
} else { // c is a character
// Single-character escapes (will terminate escape loop)
if (c == 'n') {
inEscape = false;
strOut.append('\n');
} else if(c == 't') {
inEscape = false;
strOut.append('\t');
} else if(c == 'b') {
inEscape = false;
strOut.append('\b');
} else if(c == 'r') {
inEscape = false;
strOut.append('\r');
} else if(c == 'f') {
inEscape = false;
strOut.append('\f');
} else if(c == '\\') {
inEscape = false;
strOut.append('\\');
} else if(c == '\'') {
inEscape = false;
strOut.append('\'');
} else if(c == '"') {
inEscape = false;
strOut.append('"');
} else {
// Saw illegal character, after escape character '\'
System.err.println(ErrorType.SYNTAX_ERROR, "Illegal character escape sequence, unrecognised escape: \\" + c);
}
}
} else if(strEsc.length() == 1) { // Second character (possibly)
if (c >= 48 && c <= 55) { // c is a digit [0-7]
strEsc += c; // Save to buffer
if (!cbOctal3) { // Terminate since !cbOctal3
inEscape = false;
}
} else {
inEscape = false; // Terminate since c is not a digit
chrBuf = c; // Save dangling character
}
} else if(strEsc.length() == 2) { // Third character (possibly)
if (cbOctal3 && c >= 48 && c <= 55) {
strEsc += c; // Save to buffer
} else {
chrBuf = c; // Save dangling character
}
inEscape = false; // Will always terminate after third character, no matter what
}
// Did escape sequence terminate, at character c?
if (!inEscape && strEsc.length() > 0) {
// strEsc is legal 1-3 digit octal char code, convert and add
strOut.append((char)Integer.parseInt(strEsc, 8));
if (chrBuf != null) { // There was a dangling character
// Check for chained escape sequences (e.g. \10\10)
if (chrBuf == '\\') {
inEscape = true; // Enter escape
strEsc = ""; // Reset escape buffer
chrBuf = null; // Reset dangling character buffer
cbOctal3 = true; // Reset cbOctal3 flag
} else {
strOut.append(chrBuf);
}
}
}
}
}
// Check for EOL-terminated escape sequence (special case)
if (inEscape) {
// strEsc is legal 1-3 digit octal char code, convert and add
strOut.append((char)Integer.parseInt(strEsc, 8));
if (chrBuf != null) { // There was a dangling character
strOut.append(chrBuf);
}
}
return strOut.toString();
}
我希望这会对你有所帮助。
答案 1 :(得分:1)
Apache commons StringEscapeUtils.unescapeJava(...)
方法将完成这项工作。虽然从javadoc描述中不清楚,但这些方法处理unicode转义以及“普通”Java String转义。