Question

我想搜索一个数组，例如＆＃34; new＆＃34; ＆＃34;纽约＆＃34; ＆＃34;其他＆＃34; ＆＃34;东西＆＃34 ;, 并且只组合构成一个州的话语的那些。

在这个例子中，我希望将状态匹配组合在数组中：

由此：

<?php 
$states = array("new york", "Nevada");
$names = array("something", "green", "something", "yellow", "new", "york", "new","jersey");

对此：

$names = ( "something", "green", "something", "yellow", "new york", "new jersey");

因此改变名称数组以组合状态。

Answer 1

在查看解决方案之前，请先看看两个假设： 1.以$ names检查并发数组元素。 2.检查$ States。

$states = array("new york", "Nevada");
$names  = array("something", "green", "something", "yellow", "new", "york", "new","jersey");
foreach($names as $k => $v) {
    $combined_names = $names[$k]." ".$names[$k+1];
    if (in_array($combined_names, $states)) {
        $names[] = $combined_names;
        $names[$k] = $names[$k+1] = '';
    } 
}
$result = array_values(array_filter($names));

输出：

Array
(
  [0] => something
  [1] => green
  [2] => something
  [3] => yellow
  [4] => new
  [5] => jersey
  [6] => new york
)

Answer 2

假设您可以在注释中解决“新泽西”问题，以下内容会将一个单词数组映射到目标数组（在本例中为状态）。然后对生成的数组进行重复数据删除并重新编制索引。

如果名称只需匹配目标字符串中的整个单词，stripos测试可以更改为更高级的preg_match;

<?php 
$states = array("new york", "Nevada");
$names = array("something", "green", "something", "yellow", "new", "york", "new","jersey");

$result = array_map(function ($e) use ($states) {
    foreach ($states as $state) {
        // The moment a match is found, return it
        if (stripos($state, $e) !== false)
        {
            return $state;
        }
    }

    // If no match was found, fall back to the word in the original array
    return $e;
}, $names);

print_r(array_values(array_unique($result)));

=

Array
(
    [0] => something
    [1] => green
    [2] => yellow
    [3] => new york
    [4] => jersey
)

从PHP数组

2 个答案: