Question

我有一个数据库，我需要使用CriteriaBuilder从Java加入。

到目前为止我有这个代码：

CriteriaBuilder cb = entman.getCriteriaBuilder();
    CriteriaQuery<Company> query = cb.createQuery(Company.class);
    Root<Employee> teacher = query.from(Employee.class);
    Join<Employee, Company> employees = teacher.join("id");
    query.select(employees).where(cb.equal(teacher.get("name"), ""));

    List<Company> results = entman.createQuery(query).getResultList();

    return results;

运行此代码后（使用springboot）我收到此错误：无法加入基本类型的属性

有谁知道我该怎么做才能让它发挥作用？

PS：如果需要，我会提供任何其他信息。提前致谢。 company database employee database

L.E .: 雇员：

@Entity
public class Employee {

    @Id
    @GeneratedValue
    private Long id;

    @Column(nullable = false)
    @Size(min = 1)
    private String name;

    @Column(nullable = false)
    @Temporal(TemporalType.DATE)
    private Date hire_date;

    @ManyToOne
    //@JoinColumn(name = "id")
    private Company company;

    public Employee() {}

    public Employee(Long id, String name, Date date, Company company) {
        setId(id);
        setName(name);
        setHire_date(date);
        setCompany(company);
    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public Date getHire_date() {
        return hire_date;
    }

    public void setHire_date(Date hire_date) {
        this.hire_date = hire_date;
    }

    public Company getCompany() {
        return company;
    }

    public void setCompany(Company company) {
        this.company = company;
    }
}

公司：

@Entity
public class Company {

    @Id
    @GeneratedValue
    private Long id;

    @Column(nullable = false)
    @Size(min = 1)
    private String name;

    @OneToMany(mappedBy="company", cascade = CascadeType.ALL, fetch=FetchType.EAGER, orphanRemoval=true)
    private Collection<Employee> employees;

    public Company() {}

    public Company(Long id, String name) {
        setId(id);
        setName(name);
    }

    public Company(Long id, String name, Collection<Employee> employees) {
        setId(id);
        setName(name);
        setEmployees(employees);
    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public Collection<Employee> getEmployees() 
    {
        return employees;
    }

    public void setEmployees(Collection<Employee> employees) {
        this.employees = employees;
    }

    @Override
    public String toString() {
        return "Company [id=" + id + ", name=" + name + ", employees=" + employees.toString() + "]";
    }

}

Answer 1

您需要拥有Teacher元素，而不是对id的引用，因为您无法加入@Column字段......

从@Column更改ID映射：

@Column(name = "id")
private Integer id;

与@ManyToOne（或所需的）关联：

@ManyToOne
@JoinColumn(name = "id")
private Teacher teacher;

在此之后，join将按预期工作。

如何使用条件构建器在Java上进行连接

1 个答案: