我尝试从.net网络服务中获取数据。我得到像this这样的json响应。但我无法获取图像并将其设置为图像视图。我所做的编码如下。给出解决方案
public class DisplayList extends ListActivity {
private static final String TAG_CATEGORY = "main_name";
private static final String TAG_SUBCAT = "cat_name";
private static final String TAG_CODE = "code";
private static final String TAG_NAME = "name";
private static final String TAG_RATE = "rate";
private static final String TAG_RATE2 = "rate2";
private static final String TAG_RATE3 = "rate3";
private static final String TAG_IMAGE = "img";
ArrayList<DetailsVO> mListCustomerDetails = null;
ArrayList<HashMap<String, String>> productlist;
String subc;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_display_list);
productlist = new ArrayList<HashMap<String, String>>();
Bundle extras = getIntent().getExtras();
if (extras != null) {
subc = extras.getString("Subcat");
}
new AsyncCallSoap1().execute();
productlist.clear();
}
public class AsyncCallSoap1 extends AsyncTask<String,Void,String> {
private final ProgressDialog dialog=new ProgressDialog(DisplayList.this);
//String tal_on=taluka.getText().toString();
@Override
protected String doInBackground(String... params) {
CallSoap com=new CallSoap();
String SOAP_ACTION="http://tempuri.org/IprotechService/SelectSuCatgeory";
String OPERATION_NAME="SelectSuCatgeory";
String response = com.getDetails(OPERATION_NAME,SOAP_ACTION);
if(response!=null){
try {
JSONArray array1 = new JSONArray(response);
for(int i=0;i<array1.length();i++)
{
JSONObject obj1 = array1.getJSONObject(i);
String out_category = obj1.getString(TAG_CATEGORY);
String out_subcat = obj1.getString(TAG_SUBCAT);
String out_code = obj1.getString(TAG_CODE);
String out_name = obj1.getString(TAG_NAME);
String out_rate = obj1.getString(TAG_RATE);
String out_rate2 = obj1.getString(TAG_RATE2);
String out_rate3 = obj1.getString(TAG_RATE3);
String out_img = obj1.getString(TAG_IMAGE);
// Toast.makeText(DetailsList.this, categoryId, Toast.LENGTH_LONG).show();
if(subc.equalsIgnoreCase(out_subcat)){
HashMap<String, String> details = new HashMap<String, String>();
details.put(TAG_NAME,out_name);
details.put(TAG_RATE,"Rs. "+out_rate);
details.put(TAG_IMAGE,out_img);
productlist.add(details);
}
}
} catch (JSONException e) {
e.printStackTrace();
}
}
return response;
}
@Override
protected void onPreExecute() {
super.onPreExecute();
//Showing progress dialog
dialog.setMessage("Please wait...");
dialog.setCancelable(false);
dialog.show();
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
dialog.dismiss();
ListAdapter adapter = new SimpleAdapter(
DisplayList.this, productlist,
R.layout.row_layout, new String[] {TAG_IMAGE, TAG_NAME, TAG_RATE,},
new int[] { R.id.imageView2,R.id.textView2,
R.id.textView3});
// contactList.notifyDataSetChanged();
setListAdapter(adapter);
}
}
}
答案 0 :(得分:1)
您应该询问后端人员图像的根文件夹是什么。
它应该如下所示: &#34; http://domain.com/images/&#34;
然后你将只是连接图像名称:
String image_name = "toy.png"
String image_url = "http://domain.com/images/"+image_name;
然后使用毕加索或其他方式将图片加载到图片视图中:
Picasso.with(context)
.load(image_url)
.resize(50, 50)
.centerCrop()
.into(imageView)
答案 1 :(得分:0)
用于在android中的imageview中显示图像,首先编译滑动到你的gradle中。
compile 'com.github.bumptech.glide:glide:3.7.0'
然后在你的适配器getView方法中从这个url获取图像。
ImageView imageView = (ImageView) itemView.findViewById(R.id.imageView);
GlideDrawableImageViewTarget imageViewTarget = new GlideDrawableImageViewTarget(imageView);
Glide.with(mContext).load(url).placeholder(R.raw.loading).error( R.drawable.nophoto ).into(imageViewTarget);
答案 2 :(得分:0)
如果数据库中的图像为byteArray
,则
接收byteArray
,然后将其转换为位图。使用,
Bitmap bitmap = BitmapFactory.decodeByteArray(byteArray , 0, byteArray.length);
如果您有image as an url
表示,则可以使用某些库,
这可能会对你有所帮助。