图像输入不会显示在$ _FILES中
我正在尝试更新我的数据库中的图像。我有一个加载jquery的模态。单击保存修改按钮时，表单数据显示除了图像文件，而不显示在PHP的$ _FILES中。我尝试了网上找到的所有指示（php ini文件启用文件上传，图像大小很好）。如果我使用经典的提交方法，代码可以工作，但我不想要全屏刷新，我需要在ajax中完成所有操作。这是html：
$('#updatePubDevFrm').submit(function (e) {
e.preventDefault();
var data = $(this).serialize();
alert(data);
var url = '/PubDev/updatePubDev';
$.post(url, data, null, 'json')
.done(function (data) {
if (data.status === "OK") {
$('#updatePubDevModal').removeClass('md-show');
} else {
alert("update error");
}
})
.fail(function (data) {
alert("ajax error");
})
.always(function () {
});
});<div class="md-modal md-effect-1" id="updatePubDevModal" >
<div class="md-content">
<div class="modal-header">
<button class="md-close close">×</button>
<h4 class="modal-title">Update Publisher/Developer</h4>
</div>
<form id="updatePubDevFrm" class="dz-clickable dropzone" action="/PubDev/updatePubDev" method="post" enctype="multipart/form-data">
<div class="modal-body">
<div class="row dropzone">
<div class="col-lg-5">
<div class="form-group">
<label for="pubDevName">System Id of Publisher/Developer</label>
<input type="text" placeholder="Name of Publisher/Developer" name="pubDevIdDisplay" id="pubDevIdDisplay" class="form-control input-large" disabled="true">
<input type="hidden" name="pubDevId" id="pubDevId" >
</div>
<div class="form-group">
<label for="pubDevName">Name of Publisher/Developer</label>
<input type="text" placeholder="Name of Publisher/Developer" name="pubDevName-update" id="pubDevName-update" class="form-control input-large">
</div>
<div class="form-group">
<label for="date-founded">Date Founded</label>
<input type="text" placeholder="Date founded" id="date-founded-update" name="date-founded-update" class="form-control date-picker input-large">
</div>
<div class="form-group">
<label>What type of company is this?</label>
<div class="checkbox-nice">
<input type="checkbox" name="isPub-update" id="isPub-update">
<label for="date-founded-update">
This company is a publisher
</label>
</div>
<div class="checkbox-nice">
<input type="checkbox" name="isDev-update" id="isDev-update">
<label for="isDev-update">
This company is a developer
</label>
</div>
</div>
</div>
<div class="col-lg-7">
<div class="main-box clearfix main-box-frame" >
<header class="main-box-header clearfix">
<h2>Upload Publisher /Developer Logo</h2>
</header>
<div class="main-box-body clearfix imgcontainer center">
<img id="preview" src="" class="pointable" alt="No Image Available" style="max-height:100%; max-width: 100%; "/>
<div class="main-box-body clearfix">
<div id="dropzone" class="drop-zone-frame" >
<input type="file" name="image2" id="image2">
</div>
</div>
</div>
</div>
</div>
</div>
</div>
<div class="modal-footer">
<button type="submit" id="confirmUpdPubdev" class="btn btn-primary">Save Modifications.</button>
</div>
</form>
</div>
</div>
这是php代码：
public function updatePubDev() {
$fields = array();
$fields[$this->pubdev->get_id_name()] = $this->input->post('pubDevId');
$fields['name'] = $this->input->post('pubDevName-update');
if ($this->input->post('date-founded'))
$fields['date_founded'] = stampa_data_formato_DATE($this->input->post('date-founded-update'), '/');
if ($this->input->post('isPub-update'))
$fields['publisher'] = 1;
else
$fields['publisher'] = 0;
if ($this->input->post('isDev-update'))
$fields['developer'] = 1;
else
$fields['developer'] = 0;
$row_count = $this->pubdev->update($fields,$this->pubdev->get_id_name());
$file = $_FILES['image2'];
//$idPubDev = $this->input->post("pubDevName");
$ds = DIRECTORY_SEPARATOR;
$path = dirname('../') . $ds . 'application' . $ds . 'assets' . $ds . 'img' . $ds . 'pub_devs' . $ds . 'logos' . $ds;
//print_r($file);
$info = new SplFileInfo($file['name']);
//var_dump($info->getExtension());
$filename = "logo_id_" . str_pad( $this->input->post('pubDevId'), 11, "0", STR_PAD_LEFT) . "." . $info->getExtension();
$result = $this->upload->uploadfile($file, $path, $filename);
//echo "test";
if ($result['status'] === "OK") {
$logo = 'logo_id_' . str_pad($this->input->post('pubDevId'), 11, "0", STR_PAD_LEFT) . '.' . $info->getExtension();
$this->pubdev->update(array('logo' => $logo, $this->pubdev->get_id_name() => $this->input->post('pubDevId')), $this->pubdev->get_id_name());
$result['message'] = "file saved successfully";
$result['query'] = $this->db->last_query();
}
$result['update_rows']= $row_count;
echo json_encode($result);
}
我尝试了.ajax版本，但问题仍然存在，这里是修改过的jquery：
$('#updatePubDevFrm').submit(function (e) {
e.preventDefault();
var data = $(this).serialize();
var url = '/PubDev/updatePubDev';
$.ajax({
url: url,
type: "POST",
data: data,
processData: false,
contentType: false
})
.done(function (data) {
if (data.status === "OK") {
$('#updatePubDevModal').removeClass('md-show');
} else {
alert("update error!");
}
})
.fail(function (data) {
alert("ajax error!");
})
.always(function () {
});
});
这不是一个重复的问题，因为答案提供了包含图像和数据输入所需的不同属性。需要$ .ajax调用中的这两个属性：
processData: false,
contentType: false
这样，它解决了我的问题。
2 个答案:
答案 0 :(得分：1)
使用FormData代替$(this).serialize();，将processData和contentType设为false
var data = new FormData();
data.append("file", $(":file", this)[0].files[0]);
$.ajax({
url: "/PubDev/updatePubDev",
type: "POST",
data: data,
processData: false,
contentType: false
})
答案 1 :(得分：0)
请尝试使用Public Class Form1
Private WithEvents DataGridView1 As DataGridView
Private WithEvents TextBox1 As TextBox
Private WithEvents TabPage2 As TabPage
Sub New()
' This call is required by the designer.
InitializeComponent()
' Add any initialization after the InitializeComponent() call.
'Add controls to the form (usually I use the designer to do this)
Dim TabPage1 As New TabPage() With {.Name = "TabPage1", .Text = "TabPage1"}
TabPage2 = New TabPage() With {.Name = "TabPage2", .Text = "TabPage2"}
DataGridView1 = New DataGridView With {.Name = "DataGridView1", .SelectionMode = DataGridViewSelectionMode.FullRowSelect, .MultiSelect = False, .ReadOnly = True, .AllowUserToAddRows = False, .Size = New Size(TabPage1.Size.Width, TabPage2.Size.Height - 40), .Anchor = AnchorStyles.Left Or AnchorStyles.Right Or AnchorStyles.Top Or AnchorStyles.Bottom, .TabIndex = 1}
TextBox1 = New TextBox With {.Name = "TextBox1", .Top = DataGridView1.Bottom + 5, .Width = DataGridView1.Width, .Visible = True, .Anchor = AnchorStyles.Left Or AnchorStyles.Right Or AnchorStyles.Bottom, .TabIndex = 0}
TabPage2.Controls.Add(TextBox1)
TabPage2.Controls.Add(DataGridView1)
Dim TabControl1 As New TabControl() With {.Name = "TabControl1"}
TabControl1.TabPages.Add(TabPage1)
TabControl1.TabPages.Add(TabPage2)
TabControl1.Size = Me.ClientRectangle.Size
TabControl1.Anchor = AnchorStyles.Left Or AnchorStyles.Right Or AnchorStyles.Top Or AnchorStyles.Bottom
Me.Controls.Add(TabControl1)
End Sub
Private Sub DataGridView1_RowEnter(sender As Object, e As DataGridViewCellEventArgs) Handles DataGridView1.RowEnter
'I would like the textbox to fill ONLY after the user has selected a row in DataGridView1.
'The problem I am having is that the first row auto-selects once I enter the tab
Dim drw As DataRow = DirectCast(DataGridView1.Rows(e.RowIndex).DataBoundItem, DataRowView).Row
TextBox1.Text = CStr(drw(1))
End Sub
Private Sub TabPage2_Enter(sender As Object, e As EventArgs) Handles TabPage2.Enter
RefreshGrid() 'Refresh the data in the list
End Sub
Sub RefreshGrid()
'simulate a database query
DataGridView1.DataSource = Nothing
Dim dtb As New DataTable
dtb.Columns.Add("C1")
dtb.Columns.Add("C2")
dtb.Rows.Add("1", "One")
dtb.Rows.Add("2", "Two")
dtb.Rows.Add("3", "Three")
dtb.Rows.Add("4", "Four")
dtb.Rows.Add("5", "Five")
DataGridView1.DataSource = dtb
End Sub
End Class
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