我有以下查询结果:
Array
(
[0] => stdClass Object
(
[TreatmentLog_ID] => 131
[DateAdministered] => 2016-07-15
[Notes] =>
[Treatment_ID] => 144
[AmountAdministered] => 1.5
[Injectable_ID] => 2
[InjectableName] => Baytril
)
[1] => stdClass Object
(
[TreatmentLog_ID] => 133
[DateAdministered] => 2016-07-12
[Notes] =>
[Treatment_ID] => 146
[AmountAdministered] => 1.2
[Injectable_ID] => 20
[InjectableName] => Vitamin C
)
[2] => stdClass Object
(
[TreatmentLog_ID] => 133
[DateAdministered] => 2016-07-12
[Notes] =>
[Treatment_ID] => 147
[AmountAdministered] => 1.3
[Injectable_ID] => 21
[InjectableName] => Vitamin E
)
)
我希望能够将数组重组为以下内容:
Array
(
[0] => stdClass Object
(
[TreatmentLog_ID] => 131
[DateAdministered] => 2016-07-15
[Notes] =>
[Treatments] => Array
(
[0] => stdClass Object
(
[Treatment_ID] => 144
[AmountAdministered] => 1.5
[Injectable_ID] => 2
[InjectableName] => Baytril
)
)
)
[1] => stdClass Object
(
[TreatmentLog_ID] => 133
[DateAdministered] => 2016-07-12
[Notes] =>
[Treatments] => Array
(
[0] => stdClass Object
(
[Treatment_ID] => 146
[AmountAdministered] => 1.2
[Injectable_ID] => 20
[InjectableName] => Vitamin C
)
[1] => stdClass Object
(
[Treatment_ID] => 147
[AmountAdministered] => 1.3
[Injectable_ID] => 21
[InjectableName] => Vitamin E
)
)
)
)
注意如果InjectableName
,第二个数组如何将AmountAdministered
,Injectable_ID
,Treatment_ID
和array
合并到TreatmentLog_ID
处理中是一场比赛。通常使用数组不是问题,但这个让我难过。我也无法更改查询。
我怎样才能在PHP
中解决此问题?
答案 0 :(得分:1)
使用isset
和array_values
函数的解决方案:
// $arr is your initial array
$result = [];
foreach ($arr as $obj) {
$innerObj = (object)[ 'Treatment_ID' => $obj->Treatment_ID, 'AmountAdministered' => $obj->AmountAdministered,
'Injectable_ID' => $obj->Injectable_ID, 'InjectableName' => $obj->InjectableName ];
if (!isset($result[$obj->TreatmentLog_ID])) {
$result[$obj->TreatmentLog_ID] = (object)[
'TreatmentLog_ID' => $obj->TreatmentLog_ID,
'DateAdministered' => $obj->DateAdministered,
'Notes' => $obj->Notes,
'Treatments' => [$innerObj]
];
} else {
$result[$obj->TreatmentLog_ID]->Treatments[] = $innerObj;
}
}
$result = array_values($result);
print_r($result); // will output the expected result
答案 1 :(得分:0)
试试这个。
我们使用array_filter()
从$inputArray
获取具有相同TreatmentLog_ID
的所有元素。然后我们用array_map()
转换那些过滤后的元素。我们必须使用clone
创建每个元素的副本,因为它们的对象和对象是通过引用传递的。然后我们unset()
我们在副本中不需要的密钥。
<?php
$inputArray = [
0 => (object) [
'TreatmentLog_ID' => 131,
'DateAdministered' => '2016-07-15',
'Notes' => '',
'Treatment_ID' => 144,
'AmountAdministered' => 1.5,
'Injectable_ID' => 2,
'InjectableName' => 'Baytril'
],
1 => (object) [
'TreatmentLog_ID' => 133,
'DateAdministered' => '2016-07-12',
'Notes' => '',
'Treatment_ID' => 146,
'AmountAdministered' => 1.2,
'Injectable_ID' => 20,
'InjectableName' => 'Vitamin C'
],
2 => (object) [
'TreatmentLog_ID' => 133,
'DateAdministered' => '2016-07-12',
'Notes' => '',
'Treatment_ID' => 147,
'AmountAdministered' => 1.3,
'Injectable_ID' => 21,
'InjectableName' => 'Vitamin E'
],
];
$transformedArray = [];
foreach ($inputArray as $key => $value)
{
$transformedArray[$key] = [
'TreatmentLog_ID' => $value->TreatmentLog_ID,
'DateAdministered' => $value->DateAdministered,
'Notes' => $value->Notes,
'Treatments' => array_map(
function ($v) {
$copy = clone $v;
unset($copy->Notes);
unset($copy->DateAdministered);
unset($copy->TreatmentLog_ID);
return $copy;
},
array_filter($inputArray, function ($v) use ($value) {
return $v->TreatmentLog_ID == $value->TreatmentLog_ID;
})
)
];
}
var_dump($transformedArray);
这给了我:
array(3) {
[0]=>
array(4) {
["TreatmentLog_ID"]=>
int(131)
["DateAdministered"]=>
string(10) "2016-07-15"
["Notes"]=>
string(0) ""
["Treatments"]=>
array(1) {
[0]=>
object(stdClass)#5 (4) {
["Treatment_ID"]=>
int(144)
["AmountAdministered"]=>
float(1.5)
["Injectable_ID"]=>
int(2)
["InjectableName"]=>
string(7) "Baytril"
}
}
}
[1]=>
array(4) {
["TreatmentLog_ID"]=>
int(133)
["DateAdministered"]=>
string(10) "2016-07-12"
["Notes"]=>
string(0) ""
["Treatments"]=>
array(2) {
[1]=>
object(stdClass)#6 (4) {
["Treatment_ID"]=>
int(146)
["AmountAdministered"]=>
float(1.2)
["Injectable_ID"]=>
int(20)
["InjectableName"]=>
string(9) "Vitamin C"
}
[2]=>
object(stdClass)#7 (4) {
["Treatment_ID"]=>
int(147)
["AmountAdministered"]=>
float(1.3)
["Injectable_ID"]=>
int(21)
["InjectableName"]=>
string(9) "Vitamin E"
}
}
}
[2]=>
array(4) {
["TreatmentLog_ID"]=>
int(133)
["DateAdministered"]=>
string(10) "2016-07-12"
["Notes"]=>
string(0) ""
["Treatments"]=>
array(2) {
[1]=>
object(stdClass)#8 (4) {
["Treatment_ID"]=>
int(146)
["AmountAdministered"]=>
float(1.2)
["Injectable_ID"]=>
int(20)
["InjectableName"]=>
string(9) "Vitamin C"
}
[2]=>
object(stdClass)#9 (4) {
["Treatment_ID"]=>
int(147)
["AmountAdministered"]=>
float(1.3)
["Injectable_ID"]=>
int(21)
["InjectableName"]=>
string(9) "Vitamin E"
}
}
}
}
让我们分解我们构建Treatments
的方式:
'Treatments' => array_map(
function ($v) {
$copy = clone $v;
unset($copy->Notes);
unset($copy->DateAdministered);
unset($copy->TreatmentLog_ID);
return $copy;
},
array_filter($inputArray, function ($v) use ($value) {
return $v->TreatmentLog_ID == $value->TreatmentLog_ID;
})
)