Question

dbCursor = dbConnection.execute("SELECT compid, " + rowToUse + ", nameshort, namefull FROM " + tableToUse + " WHERE " + rowToUse + " IS NOT NULL")

dbCursor1 = dbConnection.execute("SELECT compid, " + rowToUse + ", nameshort, namefull FROM " + tableToUse + " WHERE " + rowToUse + " IS NOT NULL")
myList = dbCursor1.fetchall()
myRange = [i for i in range(len(myList))] # [[i] for i in range(len(myList))]

myRangeCurrent = 0

for row1 in dbCursor:
    row = myList[myRange[myRangeCurrent]]
    myRangeCurrent = myRangeCurrent + 1

给我：

Traceback (most recent call last):   File "<pyshell#176>", line 1, in
<module>
    row = myList[myRange[myRangeCurrent]] IndexError: list index out of range

范围应该与在相同的选择查询上完成的周期完全相同。或者不是？

Answer 1

检查您的SQL查询是否正确（提示：您只需要一个游标，因为您的查询相同）并打印出fetchall的结果，然后尝试打印出行及其索引。

for i, row in enumerate(dbCursor.fetchall()):
    print(i, row)

虽然，你也应该能够做到这一点

for i, row in enumerate(dbCursor):
    print(i, row)

Answer 2

cricket_007解释说从光标获取len会改变光标，所以我更改了一个光标添加代码。现在不再有out of range：

mySQL = "SELECT compid, " + rowToUse + ", nameshort, namefull FROM " + tableToUse + " WHERE " + rowToUse + " IS NOT NULL"

dbCursor = dbConnection.execute(mySQL)
dbCursor1 = dbConnection.execute(mySQL)
dbCursor2 = dbConnection.execute(mySQL)

myList = dbCursor1.fetchall()
myList2 = dbCursor2.fetchall()
myRange = list(range(len(myList2)))

myRangeCurrent = 0

for row1 in dbCursor:
    row = myList[myRange[myRangeCurrent]]
    myRangeCurrent = myRangeCurrent + 1

Python sqlite循环索引超出范围

2 个答案: