Question

这是我的代码。我想忽略~~内的任何内容。即使它包含新行，白色空格。所以我可以忽略这些评论。

for letter in code :

    tok += letter                                   #adding each character to the token.

    if not is_str and (tok == " " or tok == "\n"):  
    #ignoring whitespaces and new line if it's not a string.
        tok = ""                                    #reseting each the iterator token.

    #Always always always remember. It's not lexer's job to generate errors
    #It's the work of parser. One thing should only do one thing.

    elif re.search(r'Enter', tok):
        tokens.append("ENTER")
        tok = ""

    elif re.search(r'~(.*?|\n*?)~',tok):            
    #to ignore the comments written within ~this~
        tok = ""

Answer 1

您可以使用re.DOTALL标志：

使<div class="container"> <div class="dropdown"> <button onclick="myFunction()" class="dropbtn">Select City</button> <div id="myDropdown" class="dropdown-content"> <a href="#home">Mumbai</a> </div> </div> </div>特殊字符与任何字符匹配，包括a 的换行;如果没有此标记，'.'将匹配除换行符之外的任何内容。

'.'

<强>试验：

pattern = re.compile(r'~(.*?)~', re.DOTALL)

Answer 2

如果~字符串中不允许其他~，您可以使用：

r'~[^~]*~'

这将匹配除~之外的任何字符。

如何通过python中的正则表达式匹配新行？

2 个答案: