我的查询带来3个字段 例如,如果我有以下代码:
// Prompt for a name and print a greeting using the name.
#include <stdio.h>
#include <string.h>
int main()
{
// Prompt for a name.
printf("What is your name? ");
// Get the name.
char name[20];
scanf("%s", name); // Suspect segfault occurs here...
// Construct the greeting.
char *greeting;
char *suffix;
greeting = "Hello, ";
suffix = ", nice to meet you!";
strcat(greeting, name);
strcat(greeting, suffix);
// Display the greeting.
printf("%s", greeting);
return 0;
}
所有字段都是int类型
但我希望所有人都在一个牢房里 我认为这可能就像下面的陈述;但它没有工作
select C.ContactId,C.CityId,C.ZipCode
from Contacts C
Where c.ContactId=256
答案 0 :(得分:4)
您可以使用FORMATMESSAGE
:
SELECT FORMATMESSAGE('%i %i %i', C.ContactId, C.CityId, C.ZipCode)
FROM Contacts C
WHERE C.ContactId = 256;
的 LiveDemo
强>
答案 1 :(得分:2)
Concat有更多支持
SELECT CONCAT ( 'Happy ', 'Birthday ', 11, '/', '25' ) AS Result;
这是结果集。
生日快乐11/25
答案 2 :(得分:0)
Solution of lad2025 is elegant. But you can do this too:
select cast(C.ContactId as varchar(50)) + ',' + cast(C.CityIdas varchar(50)) + ',' + cast(C.ZipCode as varchar(50))
from Contacts C
Where c.ContactId=256