在数组中添加/删除对象

Question

我有一个数组。

[  
   {  
      tab:0,
      ip:'555.222.111.555',
      stid:'sth'
   },
   {  
      tab:0,
      ip:'123.321.231.123',
      stid:'aaa'
   },
]

现在我需要

1. 将+1添加到tab ip为555.222.111.555的{​​{1}}。
2. 删除ip为123.321.231.123的整个对象。

Answer 1

这实际上是一个对象数组，而不是数组数组。

您可以这样做：

1
2
5
6
9
11
12
14
42

Answer 2

或类似的东西

var adresses = [
  {
    tab : 0,
    ip : '555.222.111.555',
    stid : 'sth'
  },
  {
    tab : 0,
    ip : '123.321.231.123',
    stid : 'aaa'
  }
];
var results = adresses.filter((x) => x.ip != "555.222.111.555");
results.forEach((x) => {x.tab++});
console.log(results); // [ { tab: 1, ip: '123.321.231.123', stid: 'aaa' } ]

Answer 3

你绝对可以尝试这样：

＆＃13;

＆＃13;

var a = [{
  tab: 0,
  ip: '555.222.111.555',
  stid: 'sth'
}, {
  tab: 0,
  ip: '123.321.231.123',
  stid: 'aaa'
}];

// search the element in the existing array.
function search(ip) {
    for (var i = 0, len = a.length; i < len; i += 1) {
      if (a[i].ip === ip) {
        return i;
      }
    }
  }
  // adds an ip to the global storage.

function add(ip, stid) {
    debugger;
    var index = search(ip);
    if (index !== undefined) {
      a[index].tab += 1;
    } else {
      a.push({
        tab: 1,
        ip: ip,
        stid: stid
      });
    }
  }
  // remove the ip history from the storage.

function remove(ip) {
    var index = search(ip);
    if (index !== undefined) {
      a.splice(index, 1);
    }
  }
  // adds a tab of this ip.
add('123.321.231.123');
// removes the ip.
remove('555.222.111.555');

console.dir(a);

＆＃13;

＆＃13;

＆＃13;