我必须将时间范围分成15分钟的间隔。 输入时间可以是12小时或24小时格式。 joda是否提供了将时间范围切割成所需间隔的方法?
ex:
input:
startTime: 08:00 AM or 08:00 endTime: 2:00 PM or 14:00
output:
08:00, 08:15, 08:30, 08:45...............
答案 0 :(得分:0)
对于时间增量,只需使用time.plusMinutes()或time.plusHours()。 要检查greter是否比han使用time.isBefore()或time.isAfter()。
PROGRAM AT3 (input, output);
uses crt, math;
CONST
band6 = 90;
band5 = 80;
band4 = 70;
band3 = 60;
band2 = 50;
VAR
Studname : array of string;
studmark : array of integer;
flag : boolean;
studinfo : text;
input : string;
count : integer;
num : integer;
input2: integer;
highmark, lowmark : integer;
median, average : integer;
BEGIN
lowmark := 100;
highmark := 0;
median := 0;
ASSIGN (Studinfo, 'ExamResults.txt');
flag := false;
WRITELN('welcome to the Band generator.');
WRITELN('To enter student results, please enter the number of students. To see class statistics, please type zzz. To clear the screen type clear screen. And to exit the program, type exit');
While flag = false DO
ReadLN (input);
IF input = 'zzz' THEN
WHILE not EOF(Studinfo) DO
BEGIN
WRITELN(studinfo);
END;
IF input = 'exit' THEN
Flag := true;
IF input = 'clear screen' THEN
CLRSCR
ELSE
if input2 <> 0 THEN
num := input2
ELSE
WRITELN('Please enter a valid number.');
FOR count := 0 to num-1 DO
BEGIN
WRITELN('Please enter name of student', count);
read(studname[count]);
WRITE(studinfo, studname[count]);
WRITELN('Please enter mark of student', count, 'out of 100 (nearest whole number)');
read(studmark[count]); write(studinfo, studmark[count]);
IF studmark[count] >=band6 THEN
WRITELN(studinfo, 'band6');
IF studmark[count] >=band5 THEN
WRITELN(studinfo, 'band5');
IF studmark[count] >=band4 THEN
WRITELN(studinfo, 'band4');
IF studmark[count] >=band3 THEN
WRITELN(studinfo, 'band3');
IF studmark[count] >=band2 THEN
WRITELN(studinfo, 'band2');
IF studmark[count] <band2 THEN
WRITELN(studinfo, 'band1');
IF studmark[count] >= highmark THEN
highmark := studmark[count];
IF studmark[count] <= lowmark THEN
lowmark := studmark[count];
END;
median := highmark MOD 2;
CLOSE(studinfo);
END.