Question

我正在创建一个简单的应用程序，我在屏幕底部有两行视图。在横向/更宽的屏幕上，我想将顶行放到底行。

|       Portrait       |   |              Landscape                |
| AAAAAAAAAAAAAAAAAAAA |   |         AAAAAAAAAAAAAAAAAAAA          |
| BBBBBBB      CCCCCCC |   | BBBBBBB                       CCCCCCC |
------------------------   -----------------------------------------

是否有几行Swift代码可以让我执行以下操作？

If (left edge of A) > (right edge of B) then set the (bottom of A to the Bottom of B)

注 1）A总是居中的 2）B和C的大小相同 3）B连接到左边缘 4）C附在右边缘

Answer 1

当屏幕足够宽时，我找到了移动框架/组件的解决方案

@IBOutlet weak var aaaVertPosition: NSLayoutConstraint!

// in viewDidAppear
moveAaaStack

override func viewDidLayoutSubviews() {
    super.viewDidLayoutSubviews()
    moveAaaStack()
}

func moveAaaStack() {
    let aaaFrame: CGRect = selectedAaaOutlet.frame
    let bbbFrame: CGRect = selectedBbbOutlet.frame
    let leftEdgeOfAAA = aaaFrame.origin.x
    let rightEdgeOfBBB = bosFrame.origin.x + bosFrame.size.width
    print("AAA = \(leftEdgeOfAAA) & BBB = \(rightEdgeOfBBB)")
    if (leftEdgeOfAAA + 8 > rightEdgeOfBBB) {
        print("*** Moving AAA Stack down ***")
        aaaVertPosition.constant = 8
    } else {
        print("*** Moving AAA Stack up ***")
        aaaVertPosition.constant = 68.5
    }
}

Xcode Swift基于屏幕尺寸移动UIElements

1 个答案: