Question

#include <cstdlib>
#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{

    int SIZE = 10;
    int NUMBERS[SIZE];
    int i;
    int j;
    int temp;

    for((i = 0) to (SIZE - 2))
    {
           for((j = 0) to (SIZE - 2))
           {
                  if(NUMBERS[j] < NUMBERS[j + 1])
                  {
                  temp = NUMBERS[j]
                  NUMBERS[j] = NUMBERS[j+1]
                  NUMBERS[j+1] = temp
                  }
           }
    }

    cout << "Sorted list";
    cout << "===========";

    for((i = 0) to (SIZE - 1))
    {
        cout << "Number ", i + 1, ": ", NUMBERS[i]
    }


    system("PAUSE");
    return EXIT_SUCCESS;
}

我一直在：

第18行＆amp; 34：预期;' before "to" line 32: expected）'之前';'令牌

我无法弄清楚原因。非常感谢任何帮助！

Answer 1

您错过了代码中的一些;（以及其他一些代码）。试试这个版本：

using namespace std;

int main(int argc, char *argv[])
{

    int SIZE = 10;
    int NUMBERS[SIZE];

    int temp;

    for(int i = 0; i< SIZE - 2; i++)
    {
           for(int j = 0; j < SIZE - 2; j++)
           {
                  if(NUMBERS[j] < NUMBERS[j + 1])
                  {
                  temp = NUMBERS[j];
                  NUMBERS[j] = NUMBERS[j+1];
                  NUMBERS[j+1] = temp;
                  }
           }
    }

    cout << "Sorted list";
    cout << "===========";

    for(int i = 0; i < SIZE - 1; i++)
    {
        cout << "Number ", i + 1, ": ", NUMBERS[i];
    }


    system("PAUSE");
    return EXIT_SUCCESS;
}

请考虑您应该初始化NUMBERS。

Answer 2

尝试：

for(i = 0; i <= (SIZE - 2); i++)
{
       for(j = 0; j<=(SIZE - 2); j++)
       {
              if(NUMBERS[j] < NUMBERS[j + 1])
              {
              temp = NUMBERS[j];
              NUMBERS[j] = NUMBERS[j+1];
              NUMBERS[j+1] = temp;
              }
       }
}
cout << "Sorted list";
cout << "===========";

for(int i = 0; i <= SIZE - 1; i++)
{
    cout << "Number ", (i + 1), ": ", NUMBERS[i];
}
system("PAUSE");
return EXIT_SUCCESS;

Dev c ++期待`;'在“到”之前，预期`）'之前';'代币

2 个答案: