Question

ADDRESS是一个合并字段，但文档（http://server/myservice）并不清楚如何将其传递给API，因为它有街道，邮编，城市等的子字段。有没有人有一个例子如何这样做？

Answer 1

这个JSON有效：

{
  "addr1" : "first line",
  "addr2" : "second line",
  "city" : "city",
  "state": "state",
  "zip": "zip code",
  "country": "country"
}

这里的架构记录了： https://us1.api.mailchimp.com/schema/3.0/Lists/Members/MergeField.json

Answer 2

它对我有用（php）

GridBagLayout

Answer 3

合并字段可以这样传递：

'FNAME' => $contact->first_name,
'LNAME' => $contact->last_name,
'ADDRESS' => (Object)[
        'addr1' => $contact->fulladdress,
        //'addr2' => $contact->address2,
        'city' => $contact->city,
        'state' => $contact->state_region,
        'zip' => $contact->zip_postal_code,
        'country' => $contact->country->shortcode,
        'language' => $contact->language->code,
 ],

Answer 4

以防万一有人遇到相同的问题。

我创建了自己的地址类，并尝试将ADDRESS-MergeField设置为JSON字符串，如下所示：

member.MergeFields["ADDRESS"] = Newtonsoft.Json.JsonConvert.SerializeObject(MyAddressObject);

这不会设置地址，但也不会返回错误。

相反，需要设置Dictionary<string, object>：

var adr = new Dictionary<string, object>
{
    { "addr1", "123 Whatever" },
    { "addr2", "" },
    { "city", "New York" },
    { "state", "NY" },
    { "zip", "12345" },
    { "country", "US" }
};

member.MergeFields["ADDRESS"] = adr;

Answer 5

Python答案

我遇到错误，因为地址行1为空。这是一个有效的复制和粘贴代码：

gawk

Answer 6

您可以创建自己的地址类并按如下方式分配

  public class Address
    {
        [JsonProperty("addr1")]
        public string Address1 { get; set; }

        [JsonProperty("addr2")]
        public string Address2 { get; set; }

        [JsonProperty("city")]
        public string City { get; set; }

        [JsonProperty("state")]
        public string State { get; set; }

        [JsonProperty("zip")]
        public string Zip { get; set; }

        [JsonProperty("country")]
        public string Country { get; set; }

    }

     var address = new Address()
                                {
                                    Address1 = "1 Main Street,
                                    Address2 = "",
                                    City = "Brooklyn",
                                    State = "NY",
                                    Zip = "11299",
                                    Country = "US"
                                };

member.MergeFields["ADDRESS"] = address;

如何使用Mailchimp API v3创建具有ADDRESS的列表成员

6 个答案: