python多行作为一个组

Question

如果我用一个调用绘制各种不相交的行，如下所示......

>>> import matplotlib.pyplot as plt
>>> x = [random.randint(0,9) for i in range(10)]
>>> y = [random.randint(0,9) for i in range(10)]
>>> data = []
>>> for i in range(0,10,2):
...     data.append((x[i], x[i+1]))
...     data.append((y[i], y[i+1]))
... 
>>> print(data)
[(6, 4), (4, 3), (6, 5), (0, 4), (0, 0), (2, 2), (2, 0), (6, 5), (2, 5), (3, 6)]
>>> plt.plot(*data)
[<matplotlib.lines.Line2D object at 0x0000022A20046E48>, <matplotlib.lines.Line2D object at 0x0000022A2004D048>, <matplotlib.lines.Line2D object at 0x0000022A2004D9B0>, <matplotlib.lines.Line2D object at 0x0000022A20053208>, <matplotlib.lines.Line2D object at 0x0000022A20053A20>]
>>> plt.show()

我无法弄清楚如何让python / matplotlib将其视为单个图，具有相同的颜色，线宽，ect和相同的图例条目......

提前谢谢

Answer 1

如果你不介意将它们全部合并为一行而不是简单地使用plt.plot(x,y)。但是我想你想把它们分开来。为此，您可以指定绘图comamnd的样式参数，然后使用Stop matplotlib repeating labels in legend中的代码来防止多个图例条目。

import matplotlib.pyplot as plt
import numpy as np
from collections import OrderedDict

x = [np.random.randint(0,9) for i in range(10)]
y = [np.random.randint(0,9) for i in range(10)]
data = []
for i in range(0,10,2):
     data.append((x[i], x[i+1]))
     data.append((y[i], y[i+1]))

#Plot all with same style and label.
plt.plot(*data,linestyle='-',color='blue',label='LABEL')

#Single Legend Label
handles, labels = plt.gca().get_legend_handles_labels()
by_label = OrderedDict(zip(labels, handles))
plt.legend(by_label.values(), by_label.keys())

#Show Plot
plt.show()

给你

Answer 2

这个怎么样？

SELECT top 1 o.* ,trs.TRN_IDN
FROM OFFENSE o
inner join CCH_PUBLIC.dbo.TRS  trs on trs.TRS_IDN = o.TRS_IDN 
inner join CCH_PUBLIC.dbo.TRN  trn on trn.TRN_IDN = trs.TRN_IDN 
inner join CCH_PUBLIC.dbo.PERSON  p on p.IND_IDN = trn .IND_IDN 
where p.PER_IDN = @PER_IDN