Question

我有以下两个数据：

$temp = Array
(
    [@url] => url
    [@type] => image/jpeg
    [@expression] => full
    [@width] => 644
    [@height] => 429
)

$count_total = count($temp); // gives me 5, how can it give me total = 1?

Array
(
    [0] => Array
        (
            [@url] => url1
            [@type] => image/jpeg
            [@expression] => full
            [@width] => 800
            [@height] => 621
        )

    [1] => Array
        (
            [@url] => url2
            [@type] => application/x-shockwave-flash
        )

)
this is total:2 // this is correct

如何将第一个数组计为1？

Answer 1

下面的数组（由你给出）

@url, @type, @expression, @width, @height

有5个索引为$temp = Array( array( [@url] => url [@type] => image/jpeg [@expression] => full [@width] => 644 [@height] => 429 ) );的值。所以它总会给你5分。

如果你想得到计数1.你必须这样做

count($temp)

此处$temp = Array ( [0] => Array ( [@url] => url1 [@type] => image/jpeg [@expression] => full [@width] => 800 [@height] => 621 ) ) $count_total = count($temp);会为您提供输出1

Answer 2

这将给你计数1

{{1}}

Answer 3

$temp[] = Array
(
    [@url] => url
    [@type] => image/jpeg
    [@expression] => full
    [@width] => 644
    [@height] => 429
)

$count_total = count($temp);

如果你的数组在上面，你可以算作1;

Answer 4

如果您获得单个结果，请执行以下操作：

$temp = Array
(
    [@url] => url
    [@type] => image/jpeg
    [@expression] => full
    [@width] => 644
    [@height] => 429
);

单一结果：

$new_temp[0] = $temp;

现在你得到：

count($new_temp); // get 1

Answer 5

$temp = Array 
       (
       [0] => Array
              (
                   [@url] => url
                   [@type] => image/jpeg
                   [@expression] => full
                   [@width] => 644
                   [@height] => 429
               )
       );

$count_total = count($temp); //gives you 1

问题是，在你的第一个代码块中，你试图计算数组中元素的数量，在第二个块中是另一个数组的内部数据。

Answer 6

它正在计算数组中的元素数量。第一个给你5因为数组有5个元素。第二个是给你2，因为它是一个包含2个元素（数组）的多数组。

要使它返回一个，你可以把数组放在一个数组中，所以像这样：

Array([0] => Array())

我希望这能回答你的问题。

PHP中的count数组给出意外的输出

6 个答案: