Question

我正在尝试使用AJAX来检索我想在用户端显示的推送通知的详细信息，但它还没有工作。

/*
*
*  Push Notifications codelab
*  Copyright 2015 Google Inc. All rights reserved.
*
*  Licensed under the Apache License, Version 2.0 (the "License");
*  you may not use this file except in compliance with the License.
*  You may obtain a copy of the License at
*
*      https://www.apache.org/licenses/LICENSE-2.0
*
*  Unless required by applicable law or agreed to in writing, software
*  distributed under the License is distributed on an "AS IS" BASIS,
*  WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or     implied.
*  See the License for the specific language governing permissions and
*  limitations under the License
*
*/

 // Version 0.1

//'use strict';

console.log('Started', self);

self.addEventListener('install', function(event) {
    self.skipWaiting();
    console.log('Installed', event);
});

self.addEventListener('activate', function(event) {
    console.log('Activated', event);
});

self.addEventListener('push', function(event) {
    console.log('Push message', event);

    var title = 'Push message';
    var xhttp = new XMLHttpRequest();

    xhttp.open("GET", "https://www.domain.nl/devtest/1.php", false);
    xhttp.send();
    title = xhttp.responseText;

    event.waitUntil(
        self.registration.showNotification(data, {
            'body': 'The Message',
            'icon': 'images/icon.png'
        })
    );
});

当我使用GCM向客户端发送推送通知时，Chrome会在服务工作者身上出现此错误：

sw.js：39未捕获的ReferenceError：未定义XMLHttpRequest

Answer 1

XMLHttpRequest已被弃用，并且在服务工作者范围内不可用。您可以使用Fetch API。

代替XMLHttpRequest

Answer 2

为此，我们可以在fetch（）选项中设置方法和主体参数。

 fetch(url, {  
    method: 'post',  
    headers: {  
      "Content-type": "application/x-www-form-urlencoded; charset=UTF-8"  
    },  
    body: 'foo=bar&lorem=ipsum'  
  })
  .then(json)  
  .then(function (data) {  
   console.log('Request succeeded with JSON response', data);  
  })  
  .catch(function (error) {  
    console.log('Request failed', error);  
  });

如果您想使用Cookie等凭据进行抓取请求，则应将请求的凭据设置为＆＃34; include＆＃34;。

fetch(url, {  
  credentials: 'include'  
})

服务工作者和AJAX

2 个答案: