Question

我在java jsp servlet代码中遇到异常我收到了标题中提到的错误我从下面提到的stackoverflow链接尝试了解决方案，但没有用..

我的问题是将空值输入到mysql数据库中..我已经被困了两天了..

Java : Cannot format given Object as a Date

Error   C2440   'initializing': cannot convert from 'std::basic_string<char,std::char_traits<char>,std::allocator<char>>' to 'PeerNet::NetPacket *' PeerNet \vc\include\xmemory0    737

错误日志：

 import java.sql.Timestamp;    
 import java.text.ParseException;    
 import java.text.SimpleDateFormat;   
 import java.time.Instant;   
 import java.util.Date;   
 import java.util.logging.Level;   
 import java.util.logging.Logger;

 public class SetDate  
 {  
 public static java.util.Date set(String s,String f)    
 {   
 java.text.SimpleDateFormat sdf=new java.text.SimpleDateFormat(f);    
 java.util.Date date=null;   
 try  
 {    
 date=sdf.parse(s);    
 }     
 catch (ParseException ex)  
 {    
 Logger.getLogger(SetDate.class.getName()).log(Level.SEVERE, null, ex);   
 }      
 return date;     
 }    


public static String format(Object time,String f) throws ParseException   
{      
    SimpleDateFormat sdf=new SimpleDateFormat(f);       
    System.out.println("Date:- " +sdf.format(time));        
    return sdf.format(time);        
}   
}

Answer 1

更改：

public static String format(Object time,String f) throws ParseException   
{      
    SimpleDateFormat sdf=new SimpleDateFormat(f);       
    System.out.println("Date:- " +sdf.format(time));        
    return sdf.format(time);        
}

为：

public static String format(Object time,String f) throws ParseException   
{   
    if (time == null) 
        rteurn null;

    SimpleDateFormat sdf=new SimpleDateFormat(f);       
    System.out.println("Date:- " +sdf.format(time));        
    return sdf.format(time);        
}

StandardWrapperValve [jsp]：用于servlet jsp的Servlet.service（）抛出异常java.lang.IllegalArgumentException：无法将给定的Object格式化为Date

1 个答案: