Question

我在PHP中有这个数组 $ all_designs_from_select_articles 。每个索引都包含对象Design：

array:7 [▼
  0 => array:12 [▼
    0 => Design {#297 ▶}
    1 => Design {#298 ▶}
    2 => Design {#299 ▶}
    3 => Design {#300 ▶}
    4 => Design {#301 ▶}
    5 => Design {#302 ▶}
    6 => Design {#303 ▶}
    7 => Design {#304 ▶}
    8 => Design {#305 ▶}
    9 => Design {#306 ▶}
    10 => Design {#307 ▶}
    11 => Design {#308 ▶}
  ]
  1 => array:15 [▼
    0 => Design {#309 ▶}
    1 => Design {#310 ▶}
    2 => Design {#311 ▶}
    3 => Design {#312 ▶}
    4 => Design {#313 ▶}
    5 => Design {#314 ▶}
    6 => Design {#315 ▶}
    7 => Design {#316 ▶}
    8 => Design {#317 ▶}
    9 => Design {#318 ▶}
    10 => Design {#319 ▶}
    11 => Design {#320 ▶}
    12 => Design {#321 ▶}
    13 => Design {#322 ▶}
    14 => Design {#323 ▶}
  ]

]

但我想要一个包含所有设计键的数组，如下所示：

array:26 [▼

 0 => Design {#297 ▶}
 1 => Design {#298 ▶}
 2 => Design {#299 ▶}
 3 => Design {#300 ▶}
 4 => Design {#301 ▶}
 5 => Design {#302 ▶}
 6 => Design {#303 ▶}
 7 => Design {#304 ▶}
 8 => Design {#305 ▶}
 9 => Design {#306 ▶}
 10 => Design {#307 ▶}
 11 => Design {#308 ▶}

 12 => Design {#309 ▶}
 13 => Design {#310 ▶}
 14 => Design {#311 ▶}
 15 => Design {#312 ▶}
 16 => Design {#313 ▶}
 17 => Design {#314 ▶}
 18 => Design {#315 ▶}
 19 => Design {#316 ▶}
 20 => Design {#317 ▶}
 21 => Design {#318 ▶}
 22 => Design {#319 ▶}
 23 => Design {#320 ▶}
 24 => Design {#321 ▶}
 25 => Design {#322 ▶}
 26 => Design {#323 ▶}
 ...
 etc
]

这是我对API的查询并获取第一个数组值：

foreach ($search_articles as $article) {

                $all_designs_from_select_articles[] = ApiDesign::getList([
                    'article_id' => $article,
                    'visibility' => 'ALL',
                    'order' => '-POPULARITY,NAME',
                    'lang' => 'multi,es',
                ]);
            }

PHP中是否有一个函数可以执行此操作？我正在使用PHP7和框架laravel 5.2

Answer 1

您可以使用

将事后的子阵列合并在一起

$(function(){
  $( "#frmActiontest" ).submit(function( event ) {
     var url = $(this).attr('action');
          $.ajax({
          url: url,
          data: $("#frmActiontest").serialize(),
          type: $(this).attr('method')
        }).done(function(data) {
          //window.location.href="http://neuronguru.com/MedAdmin/tests/";
          window.location.reload();
          /*$('#result').html(data);
          $('#frmActiontest')[0].reset();*/
        });
      event.preventDefault();
  });
  $( ".test" ).on("click",function(event) {
        var url = $(this).data('url');
        var actionUrl = $(this).data('actionurl');
        console.log(actionUrl);
        $("#frmActiontest").attr('action',actionUrl);
        $.ajax({
          url: url,
          type: "GET",
          dataType: 'json'
        }).done(function(data) {
          data=data[0];
          $("#myModalTestLabel").html("Update Test");
          $("#simulationId").val(data.simulationId);
          $("#testTitle").val(data.testTitle);
          $("#description").val(data.description);
          //$("#contents").val(data.contents);
          $("#tid").val(data.id);
          $("#testModal").trigger("click");
          console.log(data);
        });
      event.preventDefault();
  });
  });



  this is my ajax function for the  above question

或者在创建数组期间：

$all_designs_from_select_articles = array_reduce(
    $all_designs_from_select_articles, "array_merge", []);

我认为我更喜欢后一种方法，但这是一种边缘偏好。

Answer 2

我没有测试过这段代码，但它应该像使用array_merge（）一样简单。

$newArray = array_merge($array[0], $array[1]);

提取数组索引并合并其他数组PHP中的项

2 个答案: