Question

下午好，我正在this页面上进行练习，我失败了两个测试用例：

小写单词：错误答案

任何案例单词：错误答案

我无法理解，他们的意思是我，因为在算法中，我控制大小写。

我的算法如下：

using System;

public class Palindrome
{
    public static char[] abecedario = new char[]{ 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','w','x','y','z'};
    public static char[] ABECEDARIO = new char[]{ 'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','W','X','Y','Z'};

    public static bool IsPalindrome(string str)
    {
        string strOriginal = string.Empty;
        string strInversa = string.Empty;
        for(int i = str.Length-1; i >= 0; i--)
        {
            string concatenarInversa = string.Empty;
            string concatenarOriginal = string.Empty;
            for(int j = 0; j < abecedario.Length; j++)
            {
               if(str[i] == abecedario[j] || str[i] == ABECEDARIO[j])
               {
                   concatenarInversa = abecedario[j].ToString();
               }
               if(str[(str.Length-1)-i] == abecedario[j] || str[(str.Length-1)-i] == ABECEDARIO[j] )
               {
                    concatenarOriginal = abecedario[j].ToString();
               }
               if(concatenarInversa!=string.Empty && concatenarOriginal != string.Empty)
               {
                   break;
               }
            }
            if(concatenarInversa!=string.Empty)
            {
                strInversa = strInversa + concatenarInversa;
            }
            if(concatenarOriginal != string.Empty)
            {
                strOriginal = strOriginal + concatenarOriginal;
            }
        }
        Console.WriteLine("strInversa : " + strInversa);
        Console.WriteLine("strOriginal : " + strOriginal);
        return strInversa == strOriginal;

    }


    public static void Main(string[] args)
    {
        Console.WriteLine(IsPalindrome("sEeS"));
    }
}

Answer 1

您的abecedario个变量缺少字母V（v）。试试这个：

public static char[] abecedario = new char[]{ 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
public static char[] ABECEDARIO = new char[]{ 'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};

或者（更容易打字）：

public static char[] abecedario = "abcdefghijklmnopqrstuvwxyz".ToCharArray();
public static char[] ABECEDARIO = "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToCharArray();

对于测试的示例，您当前的代码失败，请考虑单词“vee”。它不是回文，但因为你的代码忽略了字母V，它认为它是。

测试用例在段落算法回答中失败

1 个答案: